The right answer is
D.)
Hope this helps :)
Part A:
<span>a system of inequalities that only contain points D and E in the overlapping shaded regions is
5y + 2x > 12
2y - x < 12
Part B:
To verify that points D and E are solutions to the system of inequalities, we plug in the coordinate points of points D and E into the system of ineaqualities.
Part C:
</span>To <span>identify the schools that Timothy is allowed to attend we plug in the coordinate values of the points to see which satisfies the inequality y < 3x - 3. Thus Timothy is allowed to attend schools C and F.</span>
Answer:
1. X = 17/A --- answer is (A)
2. (6, 0.7) (10, 1.9)
3. $10.99D + $9.99 ≤ $100
Step-by-step explanation:
1. AX + 4AX = 51 + 2AX
5AX = 51 + 2AX .... -2AX both side
3AX = 51 .. divide 3A
X = 17/A --- answer is (A)
2. 10y = 3x -11
(2, 0.5): 3*2 -11 = - 5 10y = 10*0.5 = 5 ..... not correct
(4, 1) 3*4 - 11 = 1 10y = 10*1 = 10 ....... not correct
(6, 0.7) 3*6 - 11 = 7 10y = 10*0.7 = 7 .....Correct
(8,2.3) 3*8 -11 = 13 10y = 10*2.3 =23 ..... not correct
(10, 1.9) 3*10 -11 = 19 10y = 10*1.9 = 19 .... correct
3. 1D cost $10.99
D piece cost: $10.99D
Shipping: $9.99
No more than $100: ≤ 100
D piece DVD + Shipping withtotal no more than $100:
$10.99D + $9.99 ≤ $100
Answer:
Step-by-step explanation:
Ice sheets have one particularly special property. They allow us to go back in time and to sample accumulation, air temperature and air chemistry from another time[1]. Ice core records allow us to generate continuous reconstructions of past climate, going back at least 800,000 years[2].
Ice coring has been around since the 1950s. Ice cores have been drilled in ice sheets worldwide, but notably in Greenland[3] and Antarctica[4, 5]. High rates of snow accumulation provide excellent time resolution, and bubbles in the ice core preserve actual samples of the world’s ancient atmosphere[6].
We know that the volume of a sphere of radius r is given by
Now, we have been given the initial volume was 4,188.79 cubic centimeters. Let us find the radius at this time.
Substituting the value of volume in the above equation, we get
Now, the final volume is given by 14,137.167 cubic centimeters. Thus, we have
Now, let us find the surface areas for these two radii.
For 
Surface area is given by
Similarly, for
Therefore, the increase in the surface area is given by
Hence, the average rate at which the surface area is changing is given by
Therefore, the average rate at which the surface area is changing is given by 130.8 square centimeters per second.
