Question

The value pie/2 is a solution for the equation 2sin^2x-sinx-1=0 true or false

Answer 1

Answer:

Yes, $\frac{\pi }{2}$ is a solution

Step-by-step explanation:

Recall that $sin(\frac{\pi }{2})=1$. By replacing $\frac{\pi }{2}$ in the given trigonometric equation, we get 0 (zero) as a result, so this value is a solution:

$2*(sin(\frac{\pi }{2} ))^2-sin(\frac{\pi }{2})-1= 2*(1)^2-1-1=2-2=0$