To find the time at which both balls are at the same height, set the equations equal to each other then solve for t.
h = -16t^2 + 56t
h = -16t^2 + 156t - 248
-16t^2 + 56t = -16t^2 + 156t - 248
You can cancel out the -16t^2's to get
56t = 156t - 248
=> 0 = 100t - 248
=> 248 = 100t
=> 2.48 = t
Using this time value, plug into either equation to find the height.
h = 16(2.48)^2 + 56(2.48)
Final answer:
h = 40.4736
Hope I helped :)
Y = - 10x + 2
the slope is -10
rise over run
the line is declining 10 units for every one unit to the right
and the line hits the y-axis at + 2 so 2 = b
84.12 * 19.3.....notice how, when added, u have 3 spaces to the right of the decimal....so there is 3 decimal places..
84.12 * 19.3 = 1623.516...3 decimal places
so ur answer is : 19.3
Answer:
20 students in science class, 25 in math
Step-by-step explanation:
so let 1 classroom= x
so the other classroom= x+5
if there is a total of 45 students
x+x+5=45
2x=45-5
2x=40
x=20
Answer:
1/9(x+4)
Step-by-step explanation:
Same as the first one
