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creativ13 [48]
2 years ago
9

Given g(x) = -x – 4, find g(-5).

Mathematics
2 answers:
riadik2000 [5.3K]2 years ago
6 0

The value of g(-5) from the given. function; g(x) = -x – 4 is; g(-5) = 1

<h3>Evaluation of functions</h3>

The given function is;

  • g(x) = -x – 4

Hence, the value of g(-5) can be obtained by substituting -5 for x in the function as follows;

  • g(-5) = -(-5) -4

  • g(-5) = 5 -4

  • g(-5) = 1.

Read more on functions;

brainly.com/question/10439235

alexandr402 [8]2 years ago
6 0

Answer:

\boxed{\boxed{\huge\bf  \: g( - 5) =   1}}

Step-by-step explanation:

Given polynomial:

\bf : \sf  \longmapsto \: g(x) =  - x - 4

To find:

\bf : \sf  \longmapsto \: g( - 5)

Solution:

\bf : \sf  \longmapsto \: g(x) =  - x - 4

<em><u>Replace x with -5 on the given polynomial:</u></em>

\bf : \sf  \longmapsto \: g( - 5) =  - ( - 5 - 4)

Simplify:

<u>Remove the parenthesis of the RHS:</u>

<em>As we know that (-) and (-) equals to (+) so,</em>

\bf : \sf  \longmapsto \: g( - 5) = + 5 - 4

<u>Simply Subtract 5 and 4 on the RHS:</u>

\bf : \sf  \longmapsto \: g( - 5) =  + 1

Hence the value of g(-5) is :

\boxed{\bf \sf \: g( - 5) =  1}

______________________________________

I hope this helps!

Please let me know if you have any questions.I am joyous to help!

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Compute the sample mean and sample standard deviation for private and public colleges. Round your answers to two decimal places.
taurus [48]

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(1) The sample mean is = 6.98, the standard deviation is = 4.53 (2) The pint estimate difference is = 20.2 (3) The confidence interval limits are $ 15943.6 and $24456.4

Step-by-step explanation:

Solution

(A) The first step is to compute the mean sample and the standard deviation for private and public colleges.

Thus,

The mean and private colleges is computed as follows:

The mean and private colleges = The sum of derivation/The total number of observation

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The standard deviation is S₁ = 6.9806 = √∈ (xi - x)²/n-1

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(b) We find the point estimate of the difference between two population means

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x -y = 42.5 -22.3

=20.2

Therefore, the annual cost is =$20,200

Note: Kindly find an attached copy of the option c and the complete question stated above.

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