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creativ13 [48]
3 years ago
9

Given g(x) = -x – 4, find g(-5).

Mathematics
2 answers:
riadik2000 [5.3K]3 years ago
6 0

The value of g(-5) from the given. function; g(x) = -x – 4 is; g(-5) = 1

<h3>Evaluation of functions</h3>

The given function is;

  • g(x) = -x – 4

Hence, the value of g(-5) can be obtained by substituting -5 for x in the function as follows;

  • g(-5) = -(-5) -4

  • g(-5) = 5 -4

  • g(-5) = 1.

Read more on functions;

brainly.com/question/10439235

alexandr402 [8]3 years ago
6 0

Answer:

\boxed{\boxed{\huge\bf  \: g( - 5) =   1}}

Step-by-step explanation:

Given polynomial:

\bf : \sf  \longmapsto \: g(x) =  - x - 4

To find:

\bf : \sf  \longmapsto \: g( - 5)

Solution:

\bf : \sf  \longmapsto \: g(x) =  - x - 4

<em><u>Replace x with -5 on the given polynomial:</u></em>

\bf : \sf  \longmapsto \: g( - 5) =  - ( - 5 - 4)

Simplify:

<u>Remove the parenthesis of the RHS:</u>

<em>As we know that (-) and (-) equals to (+) so,</em>

\bf : \sf  \longmapsto \: g( - 5) = + 5 - 4

<u>Simply Subtract 5 and 4 on the RHS:</u>

\bf : \sf  \longmapsto \: g( - 5) =  + 1

Hence the value of g(-5) is :

\boxed{\bf \sf \: g( - 5) =  1}

______________________________________

I hope this helps!

Please let me know if you have any questions.I am joyous to help!

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3 years ago
How do I find the form of an equation. Is it Slope intercept form standard form or point slope form.
natulia [17]

Answer:

Step-by-step explanation:

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standard form is Ax+By=C.

point slope form is y-y₁=m(x-x₁)

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5 0
4 years ago
Which statements about the line that passes through (−2, 0) and (2, −4) are true? Select all that apply.
Gennadij [26K]

The statement about the line that passes through (-2, 0) and (2, -4) that are true are:

Option B:The line intersects the y-axis at (0, −2).

Option C: The equation of the line is y = −x − 2.

Option D: The line intersects the x-axis at (−2, 0).

<u>Solution:</u>

Given, two points are (-2, 0) and (2, -4)

We have to select the options that states true about line that passes through given two points.

Now, let us find the line equation that passes through given two points using point slope form.  

\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right) \text { where } \mathrm{m} \text { is slope and }\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { is a point on the line. }

Now slope "m" is given as:

\mathrm{m}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{0-(-4)}{-2-2}=\frac{4}{-4}=-1

Then, line equation = y – 0 = -1(x – (-2))

y = -1(x + 2)

y = -x – 2 --- equation 1

Now let us check options.

<u>Option a)</u> slope of line is 1  

We know that slope of our line is -1 so this option is wrong.

<u>Option b)</u> line intersects y – axis at (0, -2)

When line meets y – axis x becomes 0 ⇒ 0 + y + 2 = 0 ⇒ y = -2  so point is (0, -2).  

This option is right.

<u>Option c) </u>equation of line is y = -x – 2

The given equation is x + y + 2 = 0 ⇒ y = -x – 2 . so this option is correct.

<u>Option d) </u>line intersects at (-2, 0)

When line meets x – axis y becomes 0 ⇒ x + 0 + 2 = 0 ⇒ x = -2. So point is (-2, 0).

This option is right.

Hence, options b, c, d are correct.

8 0
4 years ago
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