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3 years ago

Evaluate the expression for the given value of the variable |-4b-8|+|=1-b^2|+2b^3 ; b=-2

Mathematics

1 answer:

kicyunya [14]3 years ago

4 0

The answer is -13 because the |-4(-2)-8| is 0 and the |1-(4)| is 3 and 2(-8) is -16 meaning 0+3+(-16)=-13

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Fill in the missing coefficients in the expansion of the binomial (2x^2+y^2)^4

Helga [31]

The expansion of the binomial:
( 2 x² + y² ) ^4 =
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3 years ago

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Mike says he can find a fraction equivalent to 1/10 even though 1/10 is a unit fraction is Mike correct explain

chubhunter [2.5K]

yes Mike is correct because 1/10 is also be used as a decimal which could be switched into a fraction

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3 years ago

The illuminance of a surface varies inversely with the square of its distance from the light source.If the illuminance of a surf

VashaNatasha [74]

Answer:

Distance between the surface and source of light will be increased by 6 meters.

Step-by-step explanation:

The illuminance of a surface varies inversely with the square of ts distance from the light source.

Let illuminance of the surface = x lumens per square meter

and distance from a light source = y meter.

Now x ∝ $\frac{1}{y^{2} }$

Or $x=\frac{k}{y^{2} }$ [k = proportionality constant]

Now we will find the value of k.

k = xy²

k = 120×(6)²

k = 4320

We have to calculate the distance of the source if illuminance of the surface is 30 lumens per square meter.

$30=\frac{4320}{y^{2}}$

y² = $\frac{4320}{30}$

y² = 144

y = √144 = 12 meters

So the source of the light will be shifted away from the surface = 12 - 6 = 6 meters.

6 0

3 years ago

21 POINTS!! Thank you so much!! There’s also things on my page worth lots points points as well! So if you could help with those

Art [367]

Answer:

Second one

third one

fifth one

last one

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Based on the x intercepts we can write

a(x+1)(x-5)

where a is some constant

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let's plug in (1,-8)

-8=a(1+1)(1-5)

-8= -8a

a=1

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expand this

x²-4x-5

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x²-4x-5= 2x-4

set this equal to 0

2x-4=0

2x=4

x=2

Which means that our two intervals are

(-∞,2)U(2,∞)

plug in any values in the intervals to see whether or not the function is increasing/decreation

Let's plug in 0 for (-∞,2)

2(0)-4

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It's negative so it's decreasing on this interval

DO the same thing with the other one

let's plug in x=3

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this is positive so it's increasing on this interval

Go back to the critical value of x=2 and plug this into the equation to find the max/min

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For the limit one notice that we have a positive, even degree which means the end behavior is positive, positive

what this means is as x approaches negative infinity it's infinity

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3 years ago

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IceJOKER [234]

The scale factor is 3/6 which simplifies to 1/2

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3 years ago