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Anna007 [38]
2 years ago
10

What are the non permissible values of (2n-5)/(3n+1)

Mathematics
1 answer:
myrzilka [38]2 years ago
6 0

Answer:

n= -1/3

Step-by-step explanation:

To find non permissible values (npv), focus on the denominator of an expression

In this case, the denominator is:  (3n+1)

The npv is basically the value that would make the expression equal to 0

So, make the expression in the denominator equal 0

     3n+1 = 0

Solve for n

    3n= -1

    n = (-1/3)

Thus, the npv for this equation is n= -1/3

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