How many arrangements of answers are possible for a

The population of a certain country can be modeled by the equation , where P(t)=40e^0.02t is the population in millions and t is

Akimi4 [234]

Not able to under stand what is the question

7 0

3 years ago

Greg needs $51 to go on a field trip. He has saved $12.75. He earns $6.50 per hour cleaning his neighbor's garden, and he earns

Schach [20]

B.)Yes, because the total will be $52

5 0

3 years ago

Given f(x) and g(x) = f(x) + k, look at the graph below and determine the value of k.

Anton [14]

Answer:

Given the graph $f(x) = \frac{1}{3}x -2$ and $g(x) = \frac{1}{3}x + 3$

We have to find the value of k;

Since, g(x) = f(x) +k

$\frac{1}{3}x+3 = \frac{1}{3}x-2 +k$

Subtract $\frac{1}{3}x$ from both sides we get;

$3 = -2 +k$

Add 2 to both sides we get;

$3+2 = -2 +k +2$

Simplify:

$5 = k$

or

k = 5

Therefore, the value of k = 5

3 0

3 years ago

Read 2 more answers

Ples help find the slopes in this image

emmasim [6.3K]

Answer: 1 is 1,3

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

According to an article in Newsweek, the natural ratio of girls to boys is 100:105. In China, the birth ratio is 100:114 (46.7%

mojhsa [17]

Answer:

$z=\frac{0.42 -0.467}{\sqrt{\frac{0.467(1-0.467)}{150}}}=-1.154$

$p_v =2*P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of girls born is not significantly different from 0.467

Step-by-step explanation:

Data given and notation

n=150 represent the random sample taken

X=63 represent the number of girls born

$\hat p=\frac{63}{150}=0.42$ estimated proportion of girls born

$p_o=0.467$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion if girls is 0.467.:

Null hypothesis: $p=0.467$

Alternative hypothesis: $p \neq 0.467$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.42 -0.467}{\sqrt{\frac{0.467(1-0.467)}{150}}}=-1.154$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of girls born is not significantly different from 0.467

3 0

3 years ago