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3 years ago

Which fractions are equivalent to 4/8? choose all correct answers (1/5) (2/6) (1/4) (1/2) (2/4)

Mathematics

1 answer:

ElenaW [278]3 years ago

3 0

Answer:

1/2, 2/4

Step-by-step explanation:

4/8 = (2/4) =1/2 (if you divide up and down by the same number)

so 4/8 = 1/2

next, let's simplify the choices we have: (1/5) (2/6) (1/4) (1/2) (2/4)

1/5 is already simplified

2/6 = 1/3

1/4 is already simplified

1/2 is already simplified

2/4 = 1/2

Which of these is equal to 4/8 (aka 1/2)?

Answer: 1/2 and 2/4

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4 years ago

Write 98 as the product of prime factors in ascending order

mario62 [17]

Hope this helps you....

First you need your prime numbers: 2, 3, 5, 7, 11, 13, 17 (and so on)

Begin by dividing the smallest prime into the number 98. The smallest prime is '2', so 98 / 2 is 49. 2 will not divide into 49 so find the next highest prime that will divide into 49 evenly. It is '7' so 98 as a product of primes is:

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3 years ago

Select the correct answer. Consider these three numbers written in scientific notation: 6. 5 × 103, 5. 5 × 105, and 1. 1 × 103.

Karo-lina-s [1.5K]

Scientific notation uses expression which gives easy access of order. The greatest number is $5.5 \times 10^5$ .It is greater by smallest number by 500 times.

<h3>How to convert a number to scientific notation?</h3>

It is usually of the form $a.bc.. \times 10^k$ exponent of 10 starts)

(we have 1 ≤ |a| < 10 ) (where |a| is magnitude of a without sign)

This notation is used to get some idea of how large or small a number is in terms of power of 10.

<h3>What are some basic properties of exponentiation?</h3>

If we have $a^b$ base and 'b' is called power or exponent and we call it "a is raised to the power b" (this statement might change from text to text slightly).

Exponentiation(the process of raising some number to some power) have some basic rules as:

$a^{-b} = \dfrac{1}{a^b}\\\\a^0 = 1 (a \neq 0)\\\\a^1 = a\\\\(a^b)^c = a^{b \times c}\\ a^b \times a^c = a^{b+c}$

The given numbers are:

First number = $6.5 \times 10^3 = 6500$
Second number = $5.5 \times 10^5 = 550000$
Third number = $1.1 \times 10^3 = 1100$

The smallest number is 1,100 and greatest is 550,000

Getting the division to get to know how many times the greatest number is larger than the smallest number, we get:

$\dfrac{5.5 \times 10^5}{1.1 \times 10^3} = \dfrac{5.5 \times 10^{5-3}}{1.1} = \dfrac{5.5}{1.1} \times 10^2 = 5 \times 10^2 = 500$

Thus, it is found that greatest number is $5.5 \times 10^5$ . It is greater by smallest number by 500 times.

Learn more about scientific notation here:
brainly.com/question/3112062

6 0

3 years ago

This is a literal equation.

Aleksandr [31]

Assuming this is the equation you want to operate on:
$v^{2} = (v_0)^{2} + 2\cdot a \cdot \Deltax$
$2\cdot a \cdot \Delta x = v^{2} - (v_0)^{2}$
$a = \frac{v^{2} - (v_0)^{2}}{2\cdot \Delta x}$
Before final operation we have to assume that x is not equal to 0. :)

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3 years ago

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