Yes, that's quite true. It's also a real number, and a negative number.
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As you may already be familiar, these functions f(x) and g(x) are piecewise. They consist of multiple functions with different domains.
1. For #1, the given input is f(0). Since 0≤1, you should use the first equation to solve. f(0)=3(0)-1 ➞ f(0)=-1
2. Continue to evaluate the given input for the domains given. 1≤1, therefore f(1)=3(1)-1➞f(1)=2
3. 5>1, therefore f(5)=1-2(5)➞f(5)=-9
4. -4≤1; f(-4)=3(-4)-1➞f(-4)=-13
5. -3<0<1; g(0)=2
6. -3≤-3; g(-3)=3(-3)-1➞g(-3)=-10
7. 1≥1; g(1)=-3(1)➞g(1)=-3
8. 3≥1; g(3)=-3(3)➞g(3)=-9
9. -5≤-3; g(-5)=3(-5)-1➞g(-5)=-16
Hope this helps! Good luck!
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Answer: The first option.
Step-by-step explanation:
This domain has no domain restrictions. Therefore, it covers all real numbers. x∈R
Answer:
do distributive property on both, so multiply 6•x and 6•-4. then multiply 7•x and 7•3.
so it'll basically be 6x - 24 = 7x + 21.
then add 24 to both sides so: 6x - 24 + 24 = 7x + 21 + 24. since -24+24=0 it'll be 6x = 7x + 21 + 24.
then add 21 + 24 and that will be 45.
so 6x = 7x + 45
then subtract 7x from both sides 6x - 7x = 7x + 45 - 7x
that'll be -x = 7x + 45 - 7x
combine like terms (7x - 7x) = 0
so -x = 45
and since x can't be negative, do the opposite signs
so instead of -x = 45, make it x = -45
Hope it helped! (sorry that's its very long just wanted to show u the steps just in case)
