D. 45 and can you answer my history please ASAP
Answer:
55
Step-by-step explanation:
Let x represent the middle integer. Then the smallest is x-2 and the largest is x+2. Your requirement is that ...
(x-2)/(x+2) > 2/3
3x -6 > 2x +4 . . . . cross multiply
x > 10 . . . . . . . . . . .add 6-2x
The smallest integer satisfying this requirement is x=11. The sum of the 5 integers is 5x = 55.
The smallest sum is 55.
Answer: 3log5(2) - 1 or ~0,29203
Step-by-step explanation:
2log5(4) - log5(10)
log5(4^2) - log5(10)
log5(4^2/10)
log5(16/10)
log5(8/5)
Log5(8) - log5(5)
log5(2^3) - 1
3log5(2) - 1
Answer:
You are <em>squaring x and -5 on the first equation</em>, and on the second equation you are <em>just squaring x and subtracting 5.</em>
Step-by-step explanation:
And since on the first equation x and -5 are in parenthesis that means that the square goes to both of them.
And the second one there is no parenthesis so the square only goes to the x.
I hope this helps you.