All categories

3 years ago

A package of 5 crackers contains 205 Calories. How many Calories are in one cracker using a double number line

Mathematics

1 answer:

natulia [17]3 years ago

7 0

Answer:

Step-by-step explanation:

since there are 205 calories in 5 crackers we can represent this as

205/5

we need to find how many calories are in one cracker, so lets take "x" as the # of calories in 1 cracker

$\frac{x}{1} =\frac{205}{5}$

cross multiply

5x=205

divide by 5 on both sides

x=41

41 calories in 1 cracker

Number line:

You might be interested in

A type of Conic where the plane is tilted and intersects only on one cone to form a bounded curve.

olga_2 [115]

Answer:

Ellipse when the (tilted) plane intersects only one cone to form a bounded curve.

Step-by-step explanation:

hope it will help :)

8 0

4 years ago

there are 2 people near the river they both want to get to the other side the boat can only take one person but how do they get

Delicious77 [7]

Answer:

They are on opposite sides of the river ( the riddle never said that they were on the same side )

One simply uses the boat to cross the river and the other person gets into the boat and takes it back to where it started.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What is the value of 64 ÷ 2 ∙ 16.

hjlf

64 : 2 · 16 = 32 · 16 = 512

4 0

3 years ago

Read 2 more answers

Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.

fredd [130]

$\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

$\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

so the ODE is indeed exact and there is a solution of the form $F(x,y)=C$ . We have

$\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)$

$\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)$

$f'(y)=0\implies f(y)=C$

$\implies F(x,y)=x^2y^3+\ln(x+y^2)=C$

With $y(1)=2$ , we have

$8+\ln9=C$

$\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}$

8 0

3 years ago

Write the following polynomial in standard<br> form: <br><br> 4x+3-4x2-10x3

Ne4ueva [31]

Answer:

− 10 x ^3 − 4 x ^2 + 4 x + 3

Step-by-step explanation:

5 0

3 years ago