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Nadusha1986 [10]
3 years ago
5

Marta is solving the equation S = 2πrh + 2πr2 for h. Which should be the result?

Mathematics
2 answers:
Bad White [126]3 years ago
5 0

Answer:

h = S - 2πr²     /2πr

Step-by-step explanation:

<em><u>Marta is solving the equation S = 2πrh + 2πr2 for h. Which should be the result? </u></em>

<em><u /></em>

To solve;

S = 2πrh + 2πr²

The first thing to do is to subtract 2πr²  from both-side of the equation

S - 2πr²  =   2πrh  +  2πr² - 2πr²

S - 2πr²  =   2πrh

Then next is to divide both-side of the equation by 2πr

S - 2πr²  /  2πr  =  2πrh /2πr

On the right-hand side of the equation 2πr at the numerator will cancel-out 2πr at the denominator, leaving us with just h  while on the left-hand side of the equation S-2πr² will be divided by 2πr)

S - 2πr²  /  2πr     =      h

Therefore the result should be h = S - 2πr²  /  2πr

geniusboy [140]3 years ago
4 0

Step-by-step explanation:

S = 2\pi  rh + 2\pi {r}^{2} h \\  \\  \therefore \: S = (2\pi  r + 2\pi {r}^{2}) h \\  \\ \therefore \: S = 2\pi  r(1 +  {r}) h \\  \\  \huge \purple{ \boxed{\therefore \: h =  \frac{S}{2\pi  r(1 +  {r})}  }}\\

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a

   $10,151   <  \mu  $11448.12

b

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Step-by-step explanation:

From the question we are told that

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      n =  [\frac{Z_{\frac{\alpha }{2}    } *  \sigma }{\mu} ]

substituting values

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