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pochemuha
2 years ago
8

Solve for x. . Simplify your answer as much as possible.

Mathematics
2 answers:
trasher [3.6K]2 years ago
5 0

For this case, we must find the value of "x" of the following equation:

2x = 15-3x

We add 3x to both sides of the equation:

2x + 3x = 15-3x + 3x\\5x = 15

We divide between 5 on both sides of the equation:

\frac {5x} {5} = \frac {15} {5}\\x = 3

Thus, the value of x is 3.

Answer:

x = 3


Nady [450]2 years ago
4 0

2x = 15 - 3x -- add 3x to both sides

5x = 15 -- divide both sides by 5

x = 3 -- simplest form

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Jack and Jim sign up with an online music store. Jack chooses 15 downloads for $19.75, and Jim chooses 40 downloads for $43.50.
lina2011 [118]
The answer would be A. <span>The registration fee is $5.50, and the cost per download is $0.95.</span>

Solution
Let x = registration fee
y = cost/downloads

Jack
15y + x = 19.75 ; x = 19.75 - 15y
Jim
40y + x = 43.50

Thus,
40y + x = 43.50
40y + <span>19.75 - 15y = 43.50
</span>25y = 23.75
y= 0.95

for x,
<span>x = 19.75 - 15y</span>
x = 19.75 - 15( 0.95)
x= 19.75 -14.25
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3 0
3 years ago
A group of hikers walked 2 1/4 km in 3/4 hour.The distance here varies directly with time. What is the constant of variation?
telo118 [61]

The distance depends on the time.

So now we need to find the constant of variation or the constant of proportionality.

To do so we must find y(the dependent variable) and x(the independent variable).

To find the constant(k) we must find y/x

Since y/x=k

Then 2.25/.75=k

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3 0
3 years ago
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What is the slope for y=0.5x+10
laila [671]

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Step-by-step explanation:

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5 0
2 years ago
Do the ratios 3/4 and 4/8 from a proportion
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Answer:

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2 years ago
In a certain community, 30% of the families own a dog, and 20% of the families that own a dog also own a cat. It is also known t
Komok [63]

Answer:

What is the probability that a randomly selected family owns a cat? 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%

Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:

Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)

So, 30% of the families own a dog = .30*100 = 30

20% of the families that own a dog also own a cat = 0.2*30 = 6

34% of all the families own a cat = 0.34*100 = 34

Dogs and cats: 6

Only dogs: 30 - 6 = 24

Only cats: 34 - 6 = 28

Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42

What is the probability that a randomly selected family owns a cat?

34/100 = 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?

A = doesn't own a dog

B = owns a cat

P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%

5 0
2 years ago
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