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larisa [96]
4 years ago
14

20 POINTS PLEASE HELP ASAP

Mathematics
1 answer:
Nezavi [6.7K]4 years ago
4 0

Answer:

Provide 3 to 4 well written sentences, summarizing the information from the video about the three regions of the 13 colonies.  

Step-by-step explanation:

Provide 3 to 4 well written sentences, summarizing the information from the video about the three regions of the 13 colonies.  

Provide 3 to 4 well written sentences, summarizing the information from the video about the three regions of the 13 colonies.  

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How would I solve for x?<br><img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bx%20-%201%7D%20%20%3D%20%20%7B3%7D%5E%7Bx%20%2B%20
kvv77 [185]
x = \frac{In (2) + In  (3)}{In (2) - In (3)}


Or

x ≈ - 4.41902258

I hope this helps, Good luck!
7 0
4 years ago
Starting at home, Emily traveled uphill to the hardware store for 60 minutes at just 6 mph. She then traveled back home along th
LenKa [72]
Its 8 mph and its not 24 mph


4 0
3 years ago
Read 2 more answers
Please need help on B
MA_775_DIABLO [31]
The LCD of 1/2 and 5/6 is equal to the LCM of 2 and 6. 

Multiples of 2 and 6
2: 2,4,6
6: 6,12,18

As you can see, the first number in both lines are 6.
4 0
3 years ago
The diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 mi
Assoli18 [71]

Answer:

Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.

Step-by-step explanation:

We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.

<em>Firstly, Let X = diameters of ball bearings</em>

The z score probability distribution for is given by;

          Z = \frac{ X - \mu}{\sigma} ~ N(0,1)

where, \mu = mean diameter = 106 millimeters

            \sigma = standard deviation = 4 millimeter

Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)

    P(X > 111) = P( \frac{ X - \mu}{\sigma} > \frac{111-106}{4} ) = P(Z > 1.25) = 1 - P(Z \leq 1.25)

                                                  = 1 - 0.89435 = 0.1056

Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.

4 0
3 years ago
What are three ratios that are equivalent to 8 : 20 8:20
goldfiish [28.3K]

Answer:

4:10 16:40 and 32:80

Step-by-step explanation:

5 0
3 years ago
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