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yKpoI14uk [10]
3 years ago
7

DeShawn uses 3/4 of a box of rice to cook dinner. The portion he uses weighs 12 ounces. Write and solve and equation to find the

weight of the full box kf rice.
Mathematics
2 answers:
Aleksandr [31]3 years ago
6 0

Answer:

16\ ounces

Step-by-step explanation:

we know that

3/4 of a box of rice weighs 12 ounces

so by proportion

Find the weight of the full box of rice

\frac{12}{(3/4)}\frac{ounces}{box} =\frac{x}{1}\frac{ounces}{box}\\ \\x=12/(3/4)\\ \\x=16\ ounces

Dovator [93]3 years ago
3 0
3/4 box = 12 oz

we first need to find 1/4 of a box. to do that divide both sides by 3

1/4 box = 4 oz

for a full box which is 4/4 multiply both sides by 4

1/4 x (4)  = 4 x (4) oz

4/4 ( or one whole) = 16 oz

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Answer:

B)

Step-by-step explanation:

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3 years ago
Suppose in the University of Manitoba, 40% of the students live in apartments. If 600 students are randomly selected, then the a
just olya [345]

Answer:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

Step-by-step explanation:

The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and X \sim Bin(n=600, p =0.4)

And we want this probability:

P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation.&#10;[tex]np=600*0.4=240\geq 10

n(1-p)=600*(1-0.4)=360 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=600*0.4=240

\sigma=\sqrt{np(1-p)}=\sqrt{600*0.4(1-0.4)}=12

And then X \sim N (\mu = 240, \sigma= 12)

And we are interested on the following probability:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

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3 years ago
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BlackZzzverrR [31]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
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