All categories

4 years ago

What is the difference between a copay and coinsurance?

Mathematics

1 answer:

bearhunter [10]4 years ago

4 0

Answer:

A deductible is the amount you pay for a service before the plan shares the cost of the service with you. A copay is a set amount you pay for the service. Coinsurance is when you pay a percentage of the cost for an item or service.

You might be interested in

What is 6/a-6 = 3/a-3 ? help me please

Alenkasestr [34]

Answer:

a=1

Step-by-step explanation:

Multiply all terms by a and cancel:

6+−6a=3+−3a

−6a+6=−3a+3(Simplify both sides of the equation)

−6a+6+3a=−3a+3+3a(Add 3a to both sides)

−3a+6=3

−3a+6−6=3−6(Subtract 6 from both sides)

−3a=−3

−3a

−3

(Divide both sides by -3)

a=1

3 0

3 years ago

Read 2 more answers

The expression (x^22) (x^7)^3 is equivalent to x^p. What is the value of p?

SpyIntel [72]

Answer:

x^87

Step-by-step explanation:

Multiplying x^22 and x^7 results in x^29.

Then we have:

(x^29)^3 = x^87

Recall that (a^b)^c = a^(bc) and that a^b*a^c = a^(b + c)

5 0

3 years ago

A courier service company wishes to estimate the proportion of people in various states that will use its services. Suppose the

a_sh-v [17]

Answer:

Probability that the sample proportion will be less than 0.03 is 0.10204.

Step-by-step explanation:

We are given that a courier service company wishes to estimate the proportion of people in various states that will use its services. Suppose the true proportion is 0.04.

Also, 469 are sampled.

Let $\hat p$ = sample proportion

The z-score probability distribution for sample proportion is given by;

Z = $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion

p = true proportion = 0.04

n = sample size = 469

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the sample proportion will be less than 0.03 is given by = P( $\hat p$ < 0.03)

P( $\hat p$ < 0.03) = P( $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < $\frac{0.03-0.04}{\sqrt{\frac{0.03(1-0.03)}{469} } }$ ) = P(Z < -1.27) = 1 - P(Z $\leq$ 1.27)

= 1 - 0.89796 = 0.10204

Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.27 in the z table which has an area of 0.89796.

Therefore, probability that the sample proportion will be less than 0.03 is 0.10204.

5 0

3 years ago

2!/0! = 2, 0 or undefined

Cloud [144]

Answer:

Undefined.

Step-by-step explanation:

Because there is a 0 in the denominator.

3 0

3 years ago

Read 2 more answers