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Hitman42 [59]
3 years ago
6

How many choices of 3 hamburger toppings are possible?

Mathematics
2 answers:
alukav5142 [94]3 years ago
7 0
There is 21 possible toppings for 3 hamburgers
Svetlanka [38]3 years ago
5 0
Take the number of toppings you were given, so let's say you were given 5 toppings. Then multiply 5 times 4 times 3 times 2 times 1 and that product would be the number of total choices. Even if it was 80 toppings just keep multiplying until you get to 1.
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Is 3/8 estimated to be closer to 0 or 1?
kolezko [41]
The cut-off point is 0.5: higher than this would be closer to 1, and lower would be closer to 0

and 3/8 is lower than 0.5: we know this because a bigger number, 4/8 is equal to 0.5

so it's closer to 0!
3 0
3 years ago
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The perimeter of a rectangle must be less than 156 feet. If the length is known to be 66 feet, find the range of possible widths
balu736 [363]

x = perimeter

x<156

length = 66

so, in order to calculate perimeter you need to add two lengths and two widths

so

156 (perimeter) - 2 (66) = two widths

156 - 132 = 24 (remember this number is two widths added together)

so 24 twice the width SO 12 would be the number that the width can't be larger than

the width has to be less than 12

w < 12

5 0
3 years ago
Give an example of each of the following or explain why you think such a set could not exist.
Oksanka [162]

Answer:

a.No

b.No

c.No

Step-by-step explanation:

a.No,Such set does not exist .A set of natural numbers is N

Every point of this set is an isolated point but no accumulation point

Accumulation point:It is defined as that point a of set Swhich every neighborhood contains infinitely many distinct point of set

(a-\epsilon,e+\epsilon)\cap S-{a}\neq\phi

Isolated point : it is defined as that point a of set S which neighborhood   does not contain any other point of set except itself

(a-\epsilon0,a+\epsilon)\cap S-{a}=\phi

Interior point of set :Let a\in S .Then a is called interior point of set when its neighborhood is a subset of set S.

a\in(a-\epsilon,e+\epsilon)\subset S

When a set is uncountable then interior point exist it is  necessary for interior points existance .

Boundary points :Let a\in S .If every non empty neighborhood of a  intersect S and complement of S.

Every member of  a set is a boundary point

b.No, such set does not exist .A non empty set with isolated point then the set have no interior points .By definition of interior point and isolated point .For example.set of natural numbers

c.No, Such set does not exist ,for example set of natural every point is an isolated point and boundary point.By definition of  boundary point and isolated point

6 0
3 years ago
Armando found the volume of the figure below by using the steps shown.
Gnesinka [82]

Answer:

Armando use the wrong demensions for the triangular prism?

Step-by-step explanation:

The height is actually 8 inches.

5 0
2 years ago
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Given that f(x) = 3x + 1 and g(x) = the quantity of 4x plus 2 divided by 3, solve for g(f(0))
Yuliya22 [10]
F(0)=1

g(1)=(4*1+2)/3 = 6/3=2

hope helped 
5 0
3 years ago
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