f(0)=64, f(1)=66, f(2)=72, f(3)=82, f(4)=96,...=2,6,10,14,...=2{1,3,5,7,...}
This can be written 2{2x+1}, so the intervals on which f(x) increases are 4x+2.
If the slope is 6/11 then, in y=mx+b form, m will be 6/11. When you multiply 6/11 and -1 you get -6/11. To get the y (-6), you have to add -60/11. So in, y=mx+b form the equation is y=6/11x+(-60/11). To make it standard form, you add negative 6/11x to both sides and then multiply by 11 to get rid of the fractions. So therefore the equation would be:
-6x + 11y = - 60
Steps of construction:
a)Draw AC = 8cm.
b)Draw perpendicular bisector XY of AC meeting AC at O.
c)From O cut off OD = ×6 cm = 3 cm along OX and OB = ×6 cm =3 cm along OY.
d)Join AB, BC, CD, and DA.
ABCD is the required rhombus
Answer: $2.88
Step-by-step explanation:
Jeff: $2.52*14= $35.28
Anna: $2.16*15= $32.40
$35.28 - $32.40= $2.88
