HELPA catapult launches a boulder with an upward velocity of 122 feet per second. The height of the boulder H in feet in after T
seconds is given by the function H(t)= -16t^2 + 122t + 10. what is the boulders maximum height. how long does it take the boulder to reach it's maximum height
1 answer:
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Answer:
x=108
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
m∠RQS≅m∠QLK -----> by corresponding angles
m∠KLM+m∠QLK=180° -----> by supplementary angles (consecutive interior angles)
we have that
m∠RQS=x° ----> given problem
so
m∠QLX=x°
m∠KLM=(x-36)° ----> given problem
substitute
