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Nastasia [14]
3 years ago
7

"Suppose that Novak Djokovic and Roger Federer are playing a tennis match in which the first player to win three sets wins the m

atch. Using D and F for the winning player of a set, in how many ways could this tennis match end
Mathematics
1 answer:
o-na [289]3 years ago
5 0

Answer: it could end in 20 different ways.

Step-by-step explanation:

This match could be

3x0 D or F

3x1 D or F

3x2 D or F

For 3x0

We have 2 options: DDD or FFF

2.P₁ = 2.1 = 2

For 3x1

We have 6 options

DFDD         FDFF

DDFD         FFDF    

FDDD         DFFF

2.3.1 = 6

For 3x2

we have 12 options:

DFDFD          FDFDF

DDFFD          FFDDF

DFFDD          FDDFF

FFDDD          DDFFF

FDFDD          DFDFF

FDDFD          DFFDF

2.3.2 = 12

In total we could have 20 outcomes.

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Step-by-step explanation:

5GP= BP

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5 0
3 years ago
Suppose a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%. A cell phon
leva [86]

Answer:

We conclude that the actual percentage of households is equal to 30%.

Step-by-step explanation:

We are given that a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%.

Their marketing people survey 150 households with the result that 43 of the households have three cell phones.

Let p = <u><em>proportion of households that have three cell phones NOT known.</em></u>

So, Null Hypothesis, H_0 : p = 30%      {means that the actual percentage of households is equal to 30%}

Alternate Hypothesis, H_A : p \neq 30%     {means that the actual percentage of households different from 30%}

The test statistics that would be used here <u>One-sample z-test for proportions;</u>

                                T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of households having three cell phones = \frac{43}{150} = 0.29

           n = sample of households = 150

So, <u><em>the test statistics</em></u>  =  \frac{0.29-0.30}{\sqrt{\frac{0.30(1-0.30)}{150} } }  

                                     =  -0.27

The value of z test statistic is -0.27.

<u>Also, P-value of the test statistics is given by;</u>

              P-value = P(Z < -0.27) = 1 - P(Z \leq 0.27)

                            = 1 - 0.6064 = <u>0.3936</u>

<u>Now, at 1% significance level the z table gives critical value of -2.58 and 2.58 for two-tailed test.</u>

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <em><u>we fail to reject our null hypothesis</u></em>.

Therefore, we conclude that the actual percentage of households is equal to 30%.

4 0
3 years ago
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