15,2,31,13
Answer:
Solution given:a number that is divisible only by itself and 1 (e.g. 2, 3, 5, 7, 11).
now
all prime numbers are:
15,2,31,13
Answer:

Step-by-step explanation:
Given number is
. We need to find the complex conjugate of the given number.
We will use the general rule to find out the complex conjugate of the number.
The complex conjugate of
will be 
And the complex conjugate of 
So, the complex conjugate of
is 
The numerator factors as (t-8)(t+4), so the whole thing is (t-8)(t+4)/(t-8). Now we can cancel the t-8 AS LONG as t isn't equal to 8, otherwise, we are canceling a zero from both numerator and denominator which is invalid. What is left is t+4.
So your choice was right.