Answer:
The functions given are:
f(x) = x²
g(x) = f(-4x-3) + 1
First, find f(-4x-3):
f(x) = x²
f(-4x-3) = (-4x-3)²
Find g(x):
g(x) = f(-4x-3) + 1
g(x) = (-4x-3)² + 1
g(x) = (-1)² (4x+3)² + 1
g(x) = (4x+3)² + 1
First take
y = (x)²
Compress the graph along x axis by multiplying x with 4
y = (4x)²
Shift the graph left by 0.75 units, by adding 3 to x term.
y = (4x+3)²
Shift the graph up by 1 unit by adding 1 to the total terms.
y = (4x+3)² +1
A
you have to solve x^2+x-5=0
So x=(-1 +/- sqrt(1^2+4*1*5))/2
x=(-1 +/- sqrt(21))/2
Step-by-step explanation:
P(X)=2x²-5x-3 is in the form ax²+bx+c
Using quadratic equation
x={-b±√(b²-4ac)}/2a
x=3,-1/2
To find the average velocity in a velocity-time graph at a particular interval, simply determine the gradient at that particular interval.
<span>a. average velocity= 4/1 </span>
<span>= 4m/s </span>
<span>b. average velocity from 1 to 2.5s= 6/(2.5-1) </span>
<span>= 4m/s </span>
<span>average velocity from 2.5 to 4.0s= 0m/s </span>
<span>average velocity from 0 to 4.0s= (4+0)/4 </span>
<span>= 1m/s </span>
<span>c. average velocity from 1.0 to 4.0s= (4/3)m/s </span>
<span>average velocity from 4.0 to 5.0s= 2/1 </span>
<span>= 2.0m/s </span>
<span>average velocity from 1.0 to 5.0s= ((4/3)+2)/4 </span>
<span>= (5/6)m/s </span>
<span>d. average velocity from 0 to 4.0s= 1.0m/s </span>
<span>average velocity from 4.0 to 5.0s= 2.0m/s </span>
<span>average velocity from 0 to 5.0s= (1.0+2.0)/5 </span>
<span>= (3/5)m/s </span>
Answer:
1130.97
Step-by-step explanation:
It was easy!
