It’s a graph please help
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Answer
given,
work = 5 J
spring stretch form 30 cm to 39 cm
x = 0.39 - 0.30 = 0.09 m
k = 1234.568 N/m
a) work when spring is stretched from 32 cm to 34 cm
x₂= 0.34 -0.30 = 0.04 m
x₁ = 0.32 - 0.30 = 0.02
W = 0.741 J
b) F = k x
25 = 1234.568 × x
x = 0.0205 m
x = 2.05 cm
Assuming the function is
For
to be differentiable, it necessarily has to be continuous. For this condition to be met, we need
For the derivative to exist, the one-sided limits of the derivative must also exist and be equal. We have
Now we solve for
and 
:
For
For the derivative to exist, the one-sided limits of the derivative must also exist and be equal. We have
Now we solve for