Question

Solve the equation id="TexFormula1" title="2 \sin ^{3} x - \sin \: x = 0 " alt="2 \sin ^{3} x - \sin \: x = 0 " align="absmiddle" class="latex-formula">
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Answer 1

Answer:

Step-by-step explanation:

$2 sin^3x-sin x=0\\sinx(2sin^2x-1)=0\\either~sin x=0,x=n\pi ,where ~n~is~an~integer.\\or~2sin ^2x-1=0\\or~1-2sin^2x=0\\cos 2x=0\\2x=(2n+1)\frac{\pi }{2} \\or~x=(2n+1)\frac{\pi }{4} ,where~n~is~an~integer.$