Question

Identify the quotient in the form a + bi. HELP ASAP PLEASE!!

Answer 1

Solving $\frac{4-5i}{2+3i}$ we get $-\frac{7}{13}-\frac{22i}{13}$

Option A is correct.

Step-by-step explanation:

We need to find the result of $\frac{4-5i}{2+3i}$

We need to remove i from the denominator. For removing i Multiplying and dividing by 2-3i:

$\frac{4-5i}{2+3i}*\frac{2-3i}{2-3i}$

Solving:

$=\frac{4-5i*2-3i}{2+3i*2-3i}\\=\frac{4(2-3i)-5i*(2-3i)}{(2)^2-(3i)^2}\\=\frac{8-12i-10i+15i^2)}{4-9i^2}\\We\,\,i^2=-1\\=\frac{8-12i-10i+15(-1))}{4-9(-1)}\\=\frac{8-12i-10i-15}{4+9}\\=\frac{8-15-12i-10i}{13}\\=\frac{-7-22i}{13}\\=-\frac{7}{13}-\frac{22i}{13}$

So, solving $\frac{4-5i}{2+3i}$ we get $-\frac{7}{13}-\frac{22i}{13}$

Option A is correct.

Keywords: Complex numbers

Learn more about Complex numbers at:

• brainly.com/question/10736268
• brainly.com/question/4678474

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