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ExtremeBDS [4]
3 years ago
10

AAAAAAAAAAAAAAAA HELP PLEASE HELP

Mathematics
2 answers:
NARA [144]3 years ago
5 0

Answer:

x=-5

Step-by-step explanation:

IRINA_888 [86]3 years ago
4 0

Answer:

x = -5

4x + 12 = -8

4x = -20

x = -5

Hope this helps

You might be interested in
2,341 ÷ 68 <br> A.32 r 42<br> B.34 r 29<br> C.34 r 42<br> D.32 r 29
son4ous [18]
B. 34 r 29 .. that’s the answer
8 0
3 years ago
Evaluate ba−1.2 when a=4 and b=12.
sergeinik [125]

Answer:

46.8

Step-by-step explanation:

3 0
2 years ago
lily bought 6 skirts and 5 coats for a total of $452.62. if lily sister bought 3 skirts and 5 coats for $289.36, what was the pr
Vikentia [17]

Answer:

$26.02

Step-by-step explanation:

Let the price of a skirt be A and that of coat be B

Iilly bought 6 skirts and 5 coats for a total of $452.62

That’s

6A + 5B = 452.62

Also, Lilly’s sister bought 3 skirts and 5 coats for $289.36

That’s

3A + 5B = 289.36

We now have two equations

1 . 6A + 5B = 452.62

2. 3A + 5B = 289.36

Subtract equation two from equation one

We have

3A = 163.26

Divide both sides by 3

3A/3 = 163.26/3

A = 54.42

A = $54.42

Now substitute 54.42 for A in either equations to get B the price of a coat

Using equation one, we have

6A + 5B = 452.62

6 x 54.42 + 5B = 456.62

326.52 + 5B = 456.62

Subtract 326.52 from both sides

326.52 - 326.52 + 5B = 456.62 - 326.52

5B = 130.1

Divide both sides by 5

5B/5 = 130.1/5

B = 26.02

= $26.02

A coat cost $26.02

3 0
3 years ago
Construct a 95% confidence interval for the population mean, μ. Assume the population has a normal distribution. A random sample
GuDViN [60]

Answer: (628.48,\ 661.52)

Step-by-step explanation:

Given : Sample size : n=16 , which is a small sample (, 30) so we use t-test.

Sample mean : \overline{x}=645 \text{ hours}

Standard deviation : \sigma = 31 \text{ hours}

Significance level : \alpha=1-0.95=0.05

Critical value : t_{n-1,\alpha/2}=2.131

The confidence interval for population mean is given by :-

\overline{x}\pm t_{n-1,\alpha/2}\dfrac{\sigma}{\sqrt{n}}\\\\=645\pm(2.131)\dfrac{31}{\sqrt{16}}\\\\\approx645\pm16.52\\\\=(645-16.52,\ 645+16.52)\\\\=(628.48,\ 661.52)

Hence, a 95% confidence interval for the population mean \mu = (628.48,\ 661.52)

6 0
3 years ago
Is the sequence arithmetic? If so, identify the common difference.
aniked [119]

Answer:

no

Step-by-step explanation:

subtract 22 by 17

subtract 33 by 22

subtract 46 by 33

you get a different answer every time

5 0
3 years ago
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