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2 years ago

Is the sequence arithmetic? If so, identify the common difference.

Mathematics

1 answer:

aniked [119]2 years ago

5 0

Answer:

Step-by-step explanation:

subtract 22 by 17

subtract 33 by 22

subtract 46 by 33

you get a different answer every time

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Jan uses 22.5 gallons of water in the shower. This amount is 7.5 gallons less than what she uses when washing her clothes. Write

arsen [322]

22.5 (shower) = X (variable used in place of the amount of water she uses to wash clothes) - 7.5 (the amount she used in the shower is 7.5 gallons less than she uses for washing clothes)

22.5 = X - 7.5 《 This is the equation.

Solve is by adding 7.5 to both sides to cancel out the negative 7.5 and you get (X = 30).

3 0

2 years ago

24 POINTS!!!!!!! <br> UNLIKE signs = ______________ and take the sign of the higher number

cricket20 [7]

They are opposite.
i hope i helped!

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3 years ago

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Write an equation for the line<br><br> With a slope of -3 and a y-intercept of 1 ________

pashok25 [27]

y=-3x+1 is the equation

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2 years ago

*UNIT RATE AND PROPORTIONS*

Advocard [28]

Answer:

Unit rate is $7 per pound.

6 pounds will cost $42

You can buy 10 pounds for $70

Step-by-step explanation:

28/4 = $7 --> Unit rate is $7 per pound.

7 × 6 = $42 --> 6 pounds will cost $42

70/7= 10 --> You can buy 10 pounds for $70

3 0

2 years ago

solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+

Alekssandra [29.7K]

Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

$\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.$

Write the augmented matrix for the system of equations

$\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)$

Find the reduced row-echelon form of the augmented matrix for the system of equations:

$\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)$