The algorithm is as follows:
1. Start
2. bottles = 0
3. While bottles != 500
3.1 Create bottle
3.2 bottle = bottle + 1
4. Switch off machine
5. Stop
Explanation:
This begins the algorithm
1. Start
This initializes bottles to 0
2. bottles = 0
The loop is repeated until 500 bottles is created
3. While bottles != 500
This creates a new bottle
3.1 Create bottle
This increments the number of bottles by 1
3.2 bottle = bottle + 1
This switches of the machine after all bottles are created
4. Switch off machine
End algorithm
5. Stop
THANKS
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To avoid this and stay on the safe side, try the following:-
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In order to prevent ports that are serving network hosts from being considered as best paths, BPDU guard should be enabled to block bpdus.
<h3>What are BPDU used for?</h3>
A bridge protocol data unit (BPDU) is known to be a kind of a data message that is known to be often transmitted in a local area network to be able to know or find loops in that given network topologies.
Hence, in the case above, In order to prevent ports that are serving network hosts from being considered as best paths, BPDU guard should be enabled to block bpdus.
See full question below
. In order to prevent ports that are serving network hosts from being considered as best paths, what should be enabled to block BPDUs?
a. BPDU filter
b. BPDU guard
c. root guard
d. BPDU drop
Learn more about ports from
brainly.com/question/10097616
#SPJ1
Answer:
c
Explanation:
assuming you are coding in python and have not install any calculation codes, the answer is most likely c
Answer:
see explaination for program code
Explanation:
scalar_product = 0
li=[]
li2=[]
#reading numbers1.txt and numbers2.txt intoli and li2 respectively
with open('numbers1.txt') as n1, open('numbers2.txt') as n2:
for line1 in n1:
li.append(int(line1))
for line2 in n2:
li2.append(int(line2))
#storing min list size into variable l
a=len(li)
b=len(li2)
if a<b:
l=a
else:
l=b
#calculating scalar product
for i in range(l):
scalar_product=scalar_product+li[i]*li2[i]
print("scalar product is",scalar_product)
