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2 years ago

SOMEONE PLEASE HELP ME PLEASE HELP ME WITH THIS!!!!!

Computers and Technology

2 answers:

zavuch27 [327]2 years ago

7 0

Answer:

The last one

Explanation:

I hope this is correct and have a great day

klemol [59]2 years ago

5 0

Answer: C

Explanation: First step in the engineering design would be to identify a problem and try to come up with a solution for it.

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A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

Hence, there are 1365 ways 

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

From the given parameters; 3 out of 15 is detective;

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

Probability that at least one is defective + Probability that at none is defective = 1

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

3 years ago

A(n) __________ is a popular way to describe relationships? (i.e., one-to-one,? one-to-many) in a relational database.

Leto [7]

A link is a popular way to describe relationships in a relational database.
There are three types of relationships (links) between tables:
1. One-to-one relationship , that allows only one record on each side of the relationship.
2. One-to-many relationship, that allows a single record in one table to be related to multiple records in another table.
3. Many-to-many relationship, in which many records in a table can link to many records in another table. F

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3 years ago

Which of the following terms describes a type of useful and legitimate software that is distributed by a developer where they do

brilliants [131]

Answer:

freeware

Explanation:

a freeware is a software that is available free of charge but is not distributed with the source code.

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3 years ago

When would you include an executive summary in a report

Hoochie [10]

Answer:

When the report is too long and complex. The executive summary provides a snapshot of what the report talks about at a high level. When the reader needs more details, they can go through the detailed report.

Explanation:

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3 years ago

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Why is this happening when I already uploaded files to my drive?

lara31 [8.8K]

Answer:

u have to upload it to your drive first

Explanation:

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2 years ago