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cricket20 [7]
3 years ago
5

Solve and graph 4x<40

Mathematics
1 answer:
allochka39001 [22]3 years ago
7 0
I am sorry , i no have graph

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A photo originally measuring 11 inches by 9 inches needs to be enlarged to a size of 55 by 45 inches. Find the scale factor of t
mariarad [96]

Answer:

scale factor = 5

Step-by-step explanation:

To determine the scale factor calculate the ratio of corresponding sides of the enlargement to the original, that is

scale factor = \frac{55}{11} = \frac{45}{9} = 5

8 0
2 years ago
During a huge snowstorm in the white mountains last year, it snowed 62.5 cm in one day. how much did it snow in meters?
makkiz [27]
Cm is a centimeter, which is one-hundredth of a meter. Or rather, one hundred centimeters is equal to one meter.

To convert cm to meters

(62.5 cm) * (1 meter/100 cm) = .625 meters
8 0
2 years ago
The fourth-grade students at Harvest School make up 0.3 of all students at the school. Witch fraction is equivalent to 0.3? -Zya
Leni [432]
3/10 or three tenths
4 0
2 years ago
Read 2 more answers
Y'all I am struggling Use the following functions to find each value below. f(x)=5x; g(x)=−2x+1; h(x)=x2+6x+8
Anni [7]

Answer:

see below the first three problems

Step-by-step explanation:

f(g(-2))

First, find g(-2) using function g(x). Then use that value as input for function f(x).

g(x) = -2x + 1

g(-2) = -2(-2) + 1

g(-2) = 5

f(x) = 5x

f(5) = 5(5)

f(5) = 25

f(g(-2)) = 25

g(h(3))

First, find h(3) using function h(x). Then use that value as input for function g(x).

h(x) = x^2 + 6x + 8

h(3) = 3^2 + 6(3) + 8 = 9 + 18 + 8

h(3) = 35

g(x) = -2x + 1

g(35) = -2(35) + 1 = -70 + 1

g(35) = -69

g(h(3)) = -69

f(g(3a))

First, find g(3a) using function g(x). Then use that value as input for function f(x).

g(x) = -2x + 1

g(3a) = -2(3a) + 1

g(3a) = -6a + 1

f(x) = 5x

f(-6a + 1) = 5(-6a + 1)

f(-6a + 1) = -30a + 5

f(g(3a)) = -30a + 5

5 0
3 years ago
The value of m <br> 1/6 m + 3 = 5 5/8
Travka [436]
Your answer would be: m = 63/4 in fraction form and m = 15.75 in decimal form.

Hope this helps and happy holidays!!
4 0
2 years ago
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