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4 years ago

What is the solution to the equation 7^3x ≈ 9 ?

1 answer:

7 0

$7^{3x}\approx9\\\\\log_77^{3x}\approx\log_79\\\\3x\approx\log_79\ \ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{x\approx\dfrac{\log_79}{3}=\frac{1}{3}\log_79=\log_79^\frac{1}{3}=\log_7\sqrt[3]9}$

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HELP IN A TEST ILL GIVE BRAINLIEST

german

Answer:

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Step-by-step explanation:

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3 years ago

Find the missing angle according to the Triangle Exterior Angle Theorem

zaharov [31]

Answer:

x = 105 degrees

Step-by-step explanation:

First, figure out the interior angle, we can do this ading the two angles and then subtracting the sum from 180 (since the interior angle of a triangle adds up to 180 degrees)

180 - (55 + 50) = 75

next, we can figure out x by taking the sum (75) and subtracting that from 180 since it is a supplementary angle:

180 - 75 = 105

x = 105

4 0

3 years ago

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Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro

Vinvika [58]

Answer:

40.1% probability that he will miss at least one of them

Step-by-step explanation:

For each target, there are only two possible outcomes. Either he hits it, or he does not. The probability of hitting a target is independent of other targets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

0.95 probaiblity of hitting a target

This means that $p = 0.95$

10 targets

This means that $n = 10$

What is the probability that he will miss at least one of them?

Either he hits all the targets, or he misses at least one of them. The sum of the probabilities of these events is decimal 1. So

$P(X = 10) + P(X < 10) = 1$

We want P(X < 10). So

$P(X < 10) = 1 - P(X = 10)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{10,10}.(0.95)^{10}.(0.05)^{0} = 0.5987$

$P(X < 10) = 1 - P(X = 10) = 1 - 0.5987 = 0.401$

40.1% probability that he will miss at least one of them

7 0

3 years ago

HELP PLS TT^TT 20 POINTS

Readme [11.4K]

Answer:

LP PLS TT^TT 20 POINTS

Kevin has prepared the following two-column proof below. He is given that angle OLN = angle LNO and he is trying to prove that OL = ON. Kevin made one error in the proof as indicated by the gold highlighted cell. Rewrite the one cell in the space provided to show the correction. (no need to rewrite the whole proof).

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3 years ago

What is the difference between a random and biased sample?

emmainna [20.7K]

Random probably wont go with other people said, biased may go for what has most reviews

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3 years ago