Answer:
800
Step-by-step explanation:
8*10*10=
8*10=
80*10=
800cm.
i broke up the problem. hope this helps!
Answer: 13%
Step-by-step explanation:
Step 1:
5000
10% of 5000=500
5% of 5000=250
25%=500+500+250= 1250 rupees
so...
5000-1250= 3750 INR, which is the original price, <u>BEFORE THE 25% WAS ADDED</u>
but..
They only want a 10% discount of the price which is 25% above the cost (5000). So essentially we want to find 15%, because 25%-10%=15%
so if...
10%=500
5%=250
15%=750 INR
this means the price with the 10% discount off 25%= 4250 INR (5000-750)
now we need to find the percentage change. For this we need to subtract the price with the 15% discount with the price BEFORE THE 25% was added
e.g 4250-3750= 500INR
Then.. divide this price with the original price before the 25% was added
e.g 500/3750= 2/15=0.13
So...
Convert 0.13 into a percentage=13%
The PERCENTAGE PROFIT of the owner is 13%
P.S Please could someone double check this answer as I am only 15 years old and may have gotten some working out wrong! Thank you
Answer:
80 persons haf fish and 152 persons had chicken
Step-by-step explanation:
Given data
let the number of persons that had fish be x and chicken be y
so
12x+9y=2544------------------1
x+y= 232------------------------2
from 2
x= 232-y
substitute the value of x in 1
12(232-y)+9y=2544
2784-12y+9y=2544
2784-3y=2544
3y= 2784-2544
3y=240
y= 240/3
y=80
put y= 80 in 2
x+80= 232
x= 232-80
x=152
Hence 80 persons haf fish and 152 persons had chicken
Answer:
19.1
Step-by-step explanation:
27 is half of 54, so that means that the second triangle is 1/2 the size of the first, meaning all sides need to be divided by 2 in order to get the answers for each side
Compound Interest
A = P(1 + r)^(n)
A = Amount, r = rate per year = 3.9% = 3.9/100 = 0.039, n = year = 3
A = P(1 + r)^(n)
A = 11000(1 + 0.039)^(3)
A = 11000(1.039)^(3) use calculator
A ≈ 12337.85
Compound Interest = A - P = 12337.85 - 11000 = 1337.85
So at the end of 3 years the Amount is ≈ £12 337.85 and the compound interest is ≈ £1 337.85
Hope this helps.