The equation of a circle with a center of (h,k) with a radius of "r" is
looking at the given equation,
5x^2 +5y^2=20
divide 5 to both sides to get
x^2+y^2 =4
now compare that to the equatio of a circle shown above
Yes, 60° is right.
Do you need me to explain why?
Step-by-step explanation:
21. x² - 4x - 5 > 0
→ (x - 5) (x - 1) > 0
{x - 5 > 0
{x + 1 > 0
{x - 5 < 0
{x + 1 < 0
{x > 5
{x > -1
{x < 5
{x < -1
= x < -1 or x > 5
therefore, option A is correct
22). 4p² - 1 ≤ 0
(2p - 1) (2p + 1) ≤ 0
{2p - 1 ≤ 0
{2p + 1 ≥ 0
{2p - 1 ≥ 0
{2p + 1 ≤ 0
{p ≤ 1/2
{p ≥ -1/2
{p ≥ 1/2
{p ≤ -1/2
1/2 ≤ p ≤ 1/2
{p ≥ 1/2
{p ≤ -1/2
-1/2 ≤ p ≤ 1/2
therefore, option A is correct.
23). y < 3x² + 3x - 6
3x² + 3x - 6 = 0
3x² + 6x - 3x - 6 = 0
3x(x +2) - 3(x +2) = 0
(x +2) (3) (-3) = 0
x = -2, 1
this is the correct ans. but their is no option similar to it.
25. x and y are root of
m² - 11m + 18 = 0
hence, x + y = 11
xy = 18
2xy = 36
now, x² + y²
= (x +y)² - 2xy
= (11)² - 36
= 121 - 36
= 85
therefore, option A is correct.
26. x² - 2x - 120
(x -1)² - 1 - 1² = 0
(x -1)² = 1 + 1²
x - 1² = 2
x - 1 = ±√2
1 ± √2
therefore, option A is correct.
hope this answer helps you dear..take care!
The circumference of a circle is given by: 2πr, where r is the radius of the circle. Equating 4π, we have 2πr = 4π so the radius of the circle is: r = 4/2 = 2. Then, the area of the circle is given by πr ^ 2 = π * (2 ^ 2) = 4π.Since the square and the circle have the same area, then: Let L be the side of the square, we have: L ^ 2 = 4π, clearing L = 2 * (π ^ (1/2))The perimeter of a square is the sum of its sides: P = L + L + L + L = 2 * (π ^ (1/2)) + 2 * (π ^ (1/2)) + 2 * (π ^ (1/2)) + 2 * (π) ^ (1/2)) P = 8 * (π ^ (1/2))
Answer:
4.16
Step-by-step explanation:
4 4/25=104/25
100/25=4
4/25=16/100
16/100=0.16
0.16+4=4.16