In the figure, AB ║ CD and m∠3 = 120°.

Write an equation in whatever form you choose with the given characteristics Parallel to y = 3/5x - 8 and passes through (0, -3)

Alona [7]

Answer (this one's written in slope-intercept form):

$y= \frac{3}{5}x -3$

Step-by-step explanation:

1) Lines that are parallel to each other have the same slope. The line $y=\frac{3}{5} x-8$ is in slope intercept form, or $y = mx + b$ form, and the number in place of $m$ represents the slope. Knowing this, it looks like $\frac{3}{5}$ is in the place of the $m$ in that equation, so $\frac{3}{5}$ is the slope - and the slope we need to use for the answer, too.

2) Once you know a point that the line must pass through and a slope, you can write an equation with point-slope form, or $y-y_1 = m (x - x_1)$ . $m$ is the slope and $x_1$ and $y_1$ are the x and y values of the point it must pass through. So, substitute $\frac{3}{5}$ for $m$ , 0 for $x_1$ , and -3 for $y_1$ . Simplify and isolate y to put it in slope-intercept form:

$y-(-3) = \frac{3}{5} (x - 0) \\y + 3 = \frac{3}{5} x - 0 \\y = \frac{3}{5} x - 3$

3) Thus, $y = \frac{3}{5} x - 3\\$ is the answer. It's written in slope-intercept form.

6 0

2 years ago

Module 1: directions: respond to this question to demonstrate your understanding of the topic/content. be sure to provide adequa

olya-2409 [2.1K]

The slope intercept form of the line whose points are (1,5) and (-2,-4) is y=3x+2.

Given two points of a line (1,5) and (-2,-4).

We have to form an equation in slop intercept form.

Equation is relationship between two or more variables which are expressed in equal to form.Equations of two variables looks like ax+by=c.

Point slope form of an equation is y=x+mc where m is slope of the line.

From two points the formula of equation is as under:

(y- $y_{1}$ )= $(y_{2} -y_{1} )/(x_{2} -x_{1} )$ *(x- $x_{1}$ )