When a linear equation is in the form y = mx + c, the c, or constant, is the intercept on the y axis, meaning it crosses the y axis at (0, 1).

The gradient (1/3 in this case) is how much the y increments (or decrements) per increase of 1 of the value of x.

This would mean that there would be one point at (0, 1), and another at (3, 2). Draw a line from these two points and beyond, and that is the graph sketched.

3 0

3 years ago

PLEASE HELP WILL GIVE BRAINLIEST IF FIRST AND RIGHT!!

inna [77]

Answer:

x=2.2

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Find the limit. use l'hospital's rule if appropriate. if there is a more elementary method, consider using it. lim x→4 x2 − 16 x

ivolga24 [154]

Probably you are supposed to compute

$\displaystyle\lim_{x\to4}\frac{x^2-16}{x^2-4x}$

Factorize the numerator and denominator, then simplify:

$\displaystyle\lim_{x\to4}\frac{(x-4)(x+4)}{x(x-4)}=\lim_{x\to4}\frac{x+4}x=\frac{4+4}4=2$

6 0

3 years ago