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sammy [17]
3 years ago
6

What is the perimeter of a square which has the same area as a circle with circumference of 4π?

Mathematics
1 answer:
Contact [7]3 years ago
6 0
The circumference of a circle is given by: 2πr, where r is the radius of the circle. Equating 4π, we have 2πr = 4π so the radius of the circle is: r = 4/2 = 2. Then, the area of the circle is given by πr ^ 2 = π * (2 ^ 2) = 4π.Since the square and the circle have the same area, then: Let L be the side of the square, we have:  L ^ 2 = 4π, clearing L = 2 * (π ^ (1/2))The perimeter of a square is the sum of its sides:  P = L + L + L + L = 2 * (π ^ (1/2)) + 2 * (π ^ (1/2)) + 2 * (π ^ (1/2)) + 2 * (π) ^ (1/2))  P = 8 * (π ^ (1/2))
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(x-3y+ 3z=-4<br><br> 2x+3y-z =15<br><br> (4x-3y- z=19<br><br> - What is the solution to the system?
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Answer:

x=5,y=1 and z=-2

Step-by-step explanation:

We are given that system of equation

x-3y+3z=-4 (I equation)

2x+3y-z=15  (II equation )

4x-3y-z=19  (III equation )

Equation II multiply by 3 then add  with equation I

Then, we get

7x+6y=41 ....(Equation IV)

Subtract equation II from equation III then we get

2x-6y=4  (equation V)

Adding equation IV and equation V then, we get

9x=45

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Substitute x=5 and y=1 in equation then, we get

5-3(1)+3z=-4

2+3z=-4

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z=\frac{-6}{3}=-2

Hence, the solution for the given system of equation is given by

x=5,y=1 and z=-2

7 0
3 years ago
Hii please help i’ll give brainliest
Novosadov [1.4K]
I think the answer would be 1/2 but i’m not sure if that’s what it’s asking
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7 0
3 years ago
Read 2 more answers
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