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den301095 [7]
3 years ago
6

Find the length of the third side. If necessary, round to the nearest tenth. 5 and 9

Mathematics
2 answers:
Vlad1618 [11]3 years ago
7 0

Answer:

is it a right triangle?

Step-by-step explanation:

expeople1 [14]3 years ago
6 0

Answer:

1. Is it a right triangle?

2. Are you looking for the hypotenuse?

Step-by-step explanation:

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Which values of a and b make this system of equations have infinitely many solutions?
Afina-wow [57]

9514 1404 393

Answer:

  a = 3, b = -8

Step-by-step explanation:

Solving the first equation for y, we get ...

  2y +16 = 6x . . . . . given

  y = 8 +3x . . . . . . . divide by 2

  y = 3x -8 . . . . . . . subtract 8

In order for the system of equations to have infinitely many solutions, the second equation must be the same as this:

  y = ax +b

  a = 3, b = -8

6 0
3 years ago
Jerry grows two different types of oranges. He wants to know which type of oranges weighs more. he takes a random sample of oran
earnstyle [38]

The answer is B (There is evidence that a Type BBB  orange typically weighs more than a Type AAA orange.) this is right on edulastic

8 0
3 years ago
For a binomial distribution with p = 0.20 and n = 100, what is the probability of obtaining a score less than or equal to x = 12
notsponge [240]
The binomial distribution is given by, 
P(X=x) =  (^{n}C_{x})p^{x} q^{n-x}
q = probability of failure = 1-0.2 = 0.8
n = 100
They have asked to find the probability <span>of obtaining a score less than or equal to 12.
</span>∴ P(X≤12) = (^{100}C_{x})(0.2)^{x} (0.8)^{100-x}
                    where, x = 0,1,2,3,4,5,6,7,8,9,10,11,12                  
∴ P(X≤12) = (^{100}C_{0})(0.2)^{0} (0.8)^{100-0} + (^{100}C_{1})(0.2)^{1} (0.8)^{100-1} + (^{100}C_{2})(0.2)^{2} (0.8)^{100-2} + (^{100}C_{3})(0.2)^{3} (0.8)^{100-3} + (^{100}C_{4})(0.2)^{4} (0.8)^{100-4} + (^{100}C_{5})(0.2)^{5} (0.8)^{100-5} + (^{100}C_{6})(0.2)^{6} (0.8)^{100-6} + (^{100}C_{7})(0.2)^{7} (0.8)^{100-7} + (^{100}C_{8})(0.2)^{8} (0.8)^{100-8} + (^{100}C_{9})(0.2)^{9} (0.8)^{100-9} + (^{100}C_{10})(0.2)^{10} (0.8)^{100-10} + (^{100}C_{11})(0.2)^{11} (0.8)^{100-11} + (^{100}C_{12})(0.2)^{12} (0.8)^{100-12}


Evaluating each term and adding them you will get,
P(X≤12) = 0.02532833572
This is the required probability. 
7 0
3 years ago
What is m in this question
solmaris [256]
-16 because you need to subtract -4 from -12
7 0
3 years ago
Find the unit rate of 42 teaspoons for 6 cups
attashe74 [19]
The answer is 7 teaspoons for one cup
6 0
3 years ago
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