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Aleks04 [339]
3 years ago
11

Complete the equation and tell which property you used for 16+31=31+

Mathematics
1 answer:
blagie [28]3 years ago
5 0
16. It's basically the problem you started with, but just reversed.
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If two supplementary angles are in the ratio of 4:5 the measure of the larger angle is
dimulka [17.4K]

Answer:

Step-by-step explanation:

Let the angles be 4x , 5x

4x + 5x = 180   { supplementary}

      9x = 180

        x = 180/9

        x = 20

Larger angle= 5x = 5* 20 = 100

6 0
3 years ago
What is the third term in the pattern with formula 8 • 4 n - 1?
sveta [45]

Answer:A

Step-by-step explanation: If you plug in 1 for n then 1-1=0 8x4=32x0=0

If you plug in 2 for n then 2-1=1 8x4=32x1=32 if you plug in 3 for n then 3-1=2 8x4=32x2=64

7 0
3 years ago
You have jogged 5 miles from the park at a rate of r miles per hour. on your way back to the park your average speed increases b
poizon [28]
1. If y<span>ou have jogged 5 miles from the park at a rate of r miles per hour, then the time you need to do this is \frac{5}{r} hours (S=v\cdot t, where S is distance, v-speed and t-time).
</span>
2. W<span>hen you run back to the park, your average speed increases by 1 mph and become r+1 mph.
</span>
3. I<span>t takes \frac{5}{r+1} hours to jog 5 miles back to the park</span>

4. T<span>he total jogging time T is \frac{5}{r} + \frac{5}{r+1} hours.</span>
<span />
5. If you jogged away from the park at an average speed of 4 miles per hour, then r+1=4 and r=3. The expression \frac{5}{r} + \frac{5}{r+1}will take look 
<span>\frac{5}{3} + \frac{5}{4}=\frac{5\cdot4+5\cdot 3}{12} =\frac{35}{12}=2.9hours.</span>



8 0
3 years ago
How would yu write two dozen eggs in a numerical or variable expression?
mestny [16]
It would be 24 because 1 dozen = 12×2= 24
3 0
3 years ago
95, 86, 78, 71, 65, 60 _____
jek_recluse [69]

Answer:

hello there here is your answer

51 is your next term.

Step-by-step explanation:

you are subtracting 9 from each number

95-9= 86

86-9=78

78-9=65

65-9=60

<u><em>60-9=51</em></u>

<u><em>so on and so on </em></u>

<u><em></em></u>

Hope this help

have a good day

bye

8 0
3 years ago
Read 2 more answers
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