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mario62 [17]
3 years ago
12

Ill give brainliest for the correct answer and explanation!!

Mathematics
2 answers:
drek231 [11]3 years ago
8 0
Your answer would be false true true false false
OleMash [197]3 years ago
7 0

Answer:

false true true false false

Step-by-step explanation:

use percentage and divide by the number given

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Sonja Koch has 90,000. She paid 350 for the title background check, 400$ for the title insurance
Pavlova-9 [17]

Answer:

89250

Step-by-step explanation:

90,000 - 350 = 89,650 - 400 = 89,250

taa-daa

3 0
3 years ago
Is 45×18 = equal to (40×10) + (40×8) + (5 × 10 + (5×8)​
astraxan [27]

Answer:

Yes it is equal to that

Step-by-step explanation:

hope it helps

5 0
2 years ago
Amy has $8 less than Maria.Together they have $30
gtnhenbr [62]
 a + m = 30
a = m - 8

(m - 8) + m = 30
2m - 8 = 30
2m = 30 + 8
2m = 38
m = 38/2
m = 19

a = m - 8
a = 19 - 8
a = 11

so Amy has $11 and Maria has $ 19
8 0
2 years ago
How many points are needed to determine a unique line
torisob [31]

In geometry, a line segment is a part of a line that is bounded by two distinct end points, and contains every point on the line between its endpoints. A closed line segment includes both endpoints, while an open line segment excludes both endpoints; a half-open line segment includes exactly one of the endpoints.

Examples of line segments include the sides of a triangle or square. More generally, when both of the segment's end points are vertices of a polygon or polyhedron, the line segment is either an edge (of that polygon or polyhedron) if they are adjacent vertices, or otherwise a diagonal. When the end points both lie on a curve such as a circle, a line segment is called a chord (of that curve).


So I think it would be 2


5 0
3 years ago
Select the basic integration formula you can use to find the indefinite integral.
kondaur [170]

Answer:

\int \dfrac{du}{u}=\log|u|+C

\int u^n du=\dfrac{u^{n+1}}{n+1}+C

\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C

Step-by-step explanation:

a.

\int \dfrac{du}{u}=\log|u|+C    [\because \int \dfrac{dx}{x}=\log |x|+C]

b.

\int u^n du=\dfrac{u^{n+1}}{n+1}+C    [\because \int x^n dx=\dfrac{x^{n+1}}{n+1}+C]

c.

\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C        [\because \dfrac{adx}{x\sqrt{x^2-a^2}}=\csc^{-1}(\dfrac{x}{a})+C]

3 0
3 years ago
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