(a−b)+a+(a+b)=45
⟹3a=45
a=15
a(a+b)=300
⟹15(15+b)=300
⟹225+15b=300
⟹15b=300−225
⟹15b15=7515
b=5
a−b=10⟹a=15⟹a+b=20
The three numbers are 10, 15, and 20.
Proof:
10+15+20=45✓
3(gameMachines) + 5(6) = 72lbs
3(gameMachines) = 42
gameMachine = 14
Answer:
4
Step-by-step explanation:
g(n) varies inversely with n.
This can be expressed alternatively as \[g(n) = \frac{k}{n}\] where k is a constant value.
Given that when n = 3, g(n) = 8.
This implies, \[8 = \frac{k}{3}\]
Simplifying the equation to solve for k, k = 8 * 3 = 24
Now when g(n) = 6, \[g(n) = \frac{k}{n}\]
\[6 = \frac{24}{n}\]
Calculating the value of n, \[n = \frac{24}{6}\] = 4
So the required value of n is 4.
Answer:
56 +136 add the rest
Step-by-step explanation:
Answer:
t=5x=3049
Step-by-step explanation:
