Answer:
Step-by-step explanation:
Draw a horizontal line at the end of the 8 meter horizontal line.
Find the area of the horizontal rectangle
L = 8 + 3
W = 2
Area = L*w
Area = 11*2
area = 22 m^2
Now do the vertical rectangle
L = 8
w = 3
Area = L*w
Area = 8 * 3
Area = 24 m^2
Total Area = 24 + 22 = 46 m^2
AB = CD = √8 ≈ 2.8 units
BC = AD = √2 ≈ 1.4 units
Area of the rectangle ABCD = 3.92 units²
Perimeter of the rectangle ABCD = 8.4 units
<h3>How to Find the Area and Perimeter of a Rectangle?</h3>
Given the coordinates of vertices of rectangle ABCD as:
- A(0,2)
- B(2,4)
- C(3,3)
- D(1,1)
To find the area and perimeter, use the distance formula to find the distance between A and B, and B and C.
Using the distance formula, we have the following:
AB = √[(2−0)² + (4−2)²]
AB = √[(2)² + (2)²]
AB = √8 ≈ 2.8 units
CD = √8 ≈ 2.8 units
BC = √[(2−3)² + (4−3)²]
BC = √[(−1)² + (1)²]
BC = √2 ≈ 1.4 units
AD = √2 ≈ 1.4 units
Area of the rectangle ABCD = (AB)(BC) = (2.8)(1.4) = 3.92 units²
Perimeter of the rectangle ABCD = 2(AB + BC) = 2(2.8 + 1.4) = 8.4 units
Learn more about the area and perimeter of rectangle on:
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Answer:
in triangle BCD
relationship between base and hypotenuse is given by cos angle
cos 71=b/h
cos71=BD/BC
cos71=67/x
x=67/cos71=205.8ft.
the length of BC to the nearest tenth of a foot is 206ft.
The answer is 11 because you do the smallest parenthesis. and work your way out.
Answer: 26=3x+2
Step-by-step explanation:
HOPE THIS HELPS =)
