Answer:
40%
Step-by-step explanation:
ok so first find the og price:
100% - 20% = 80%
so 80% = 200
let the 100% be x:
x * 0.8 = 200
x= 250
100% = 250
(difference/ og price) * 100% = the percentage decrease/ increase
(250-150/250)* 100% = 40%
OR
((the final price/ og price) * 100%) - 100%
((150/250)*100%) - 100% = 40%
There was a 40% decrease from the og price to the final price of 150.
Answer:
46
Step-by-step explanation:
Because they are alternate, duh
The probability that a student participates in both sports and drama is 
.
<h3>What is the formula for P(AUB), where A and B are any two events?</h3>
If 
and 
are any two events, then the probability of the joint event 
is given by the following formula: 
Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.
Suppose 
denotes that "a student participates in sports" and 
denotes that "a student participates in drama".
So, we have 
, 
, 
.
We want to find the probability that a student participates in both sports and drama i.e., we want to find 
.
By the above formula, we obtain:
Therefore, the probability that a student participates in both sports and drama is .
To learn more about probability, refer: brainly.com/question/24756209
#SPJ9
Step-by-step explanation:
1 Remove parentheses.
8{y}^{2}\times -3{x}^{2}{y}^{2}\times \frac{2}{3}x{y}^{4}
8y
2
×−3x
2
y
2
×
3
2
xy
4
2 Use this rule: \frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}
b
a
×
d
c
=
bd
ac
.
\frac{8{y}^{2}\times -3{x}^{2}{y}^{2}\times 2x{y}^{4}}{3}
3
8y
2
×−3x
2
y
2
×2xy
4
3 Take out the constants.
\frac{(8\times -3\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}
3
(8×−3×2)y
2
y
2
y
4
x
2
x
4 Simplify 8\times -38×−3 to -24−24.
\frac{(-24\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}
3
(−24×2)y
2
y
2
y
4
x
2
x
5 Simplify -24\times 2−24×2 to -48−48.
\frac{-48{y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}
3
−48y
2
y
2
y
4
x
2
x
6 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x
a
x
b
=x
a+b
.
\frac{-48{y}^{2+2+4}{x}^{2+1}}{3}
3
−48y
2+2+4
x
2+1
7 Simplify 2+22+2 to 44.
\frac{-48{y}^{4+4}{x}^{2+1}}{3}
3
−48y
4+4
x
2+1
8 Simplify 4+44+4 to 88.
\frac{-48{y}^{8}{x}^{2+1}}{3}
3
−48y
8
x
2+1
9 Simplify 2+12+1 to 33.
\frac{-48{y}^{8}{x}^{3}}{3}
3
−48y
8
x
3
10 Move the negative sign to the left.
-\frac{48{y}^{8}{x}^{3}}{3}
−
3
48y
8
x
3
11 Simplify \frac{48{y}^{8}{x}^{3}}{3}
3
48y
8
x
3
to 16{y}^{8}{x}^{3}16y
8
x
3
.
-16{y}^{8}{x}^{3}
−16y
8
x
3
Done
