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Gemiola [76]
2 years ago
8

Which solution set describes the set of real numbers less than or equal to -1

Mathematics
1 answer:
Igoryamba2 years ago
8 0
Easy just do the negitive numbers and then try to add to the greates number 
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Jun used 56 cm of ribbon to go around the edge of a rectangular lid. The lid was 13 cm long. What is the width of the lid?
maksim [4K]

Answer:

The width of the rectangular lid is 15 cm.

Step-by-step explanation:1. Let's review the information given to us to answer the question correctly:

Length of the ribbon used by Jun = 56 cmLength of the rectangular lid = 13 cm

2. What is the width of the lid? The ribbon used by Jun is equivalent to the perimeter of the rectangular lid, therefore:Perimeter = 2 * Length + 2 * WidthReplacing with the values we have:56 = 2 * 13 + 2 * Width56 = 26 + 2Width2Width = 56 - 262Width = 30Width = 30/2Width = 15

5 0
2 years ago
Read 2 more answers
A candle in the shape of a circular cone has a base of radius r and a height of h that is the same length as the radius. which e
ladessa [460]

Answer:

\frac{r(1-\sqrt{2})}{-3}

Step-by-step explanation:

Volume of cone = \frac{1}{3} \pi r^{2} h

Since we are given that a circular cone has a base of radius r and a height of h that is the same length as the radius

                          = \frac{1}{3} \pi r^{2} \times r

                          = \frac{1}{3} \pi r^{3}

Surface area of cone including 1 base = \pi r^{2} +\pi\times r \times \sqrt{r^2+h^2}

Since r = h

So, area = \pi r^{2} +\pi\times r \times \sqrt{r^2+r^2}

              = \pi r^{2} +\pi\times r \times \sqrt{2r^2}

              = \pi r^{2} +\pi\times r^2 \times \sqrt{2}

Ratio of volume of cone to its surface area including base :

\frac{\frac{1}{3} \pi r^{3}}{\pi r^{2} +\pi\times r^2 \times \sqrt{2}}

\frac{\frac{1}{3}r}{1+\sqrt{2}}

\frac{r}{3(1+\sqrt{2})}

Rationalizing

\frac{r}{3(1+\sqrt{2})} \times \frac{1-\sqrt{2}}{1-\sqrt{2}}

\frac{r(1-\sqrt{2})}{-3}

Hence the ratio the ratio of the volume of the candle to its surface area(including the base) is \frac{r(1-\sqrt{2})}{-3}

8 0
3 years ago
Read 2 more answers
Please help!!! Need help ASAP!
DIA [1.3K]

Answer:

ag=74 and ed=83

Step-by-step explanation:

super simple actually

3 0
3 years ago
2. Maria is monitoring the temperature of
stiks02 [169]

Here, we are required to determine after how many minutes will the two substances be at the same temperature.

The equation of when the two substances will be at the same temperature and the solution are as follows;

(a) The equation is 96.2 + 1.5(x) = 98.5 + 0.8(x).

(b) The solution is, x = 3.285minutes.

For substance A which is currently at 96.2° and rising at 1.5° each minute; It's temperature after x minutes is given as;

  • T(a) = 96.2 + 1.5(x)

For substance B which is currently at 98.5° and rising at 0.8° each minute; It's temperature after x minutes is given as;

  • T(b) = 98.5 + 0.8(x)

(a) For the two substances to be at the same temperature; T(a) must be equal to T(b).

  • T(a) = T(b)

The equation is therefore;.

96.2 + 1.5(x) = 98.5 + 0.8(x)

(b) To determine the solution;

1.5x - 0.8x = 98.5 - 96.2

0.7x = 2.3

x = 2.3/0.7

x = 3.285minutes.

Read more:

brainly.com/question/20248109

5 0
1 year ago
Gene ran 90 meters in 16.3 seconds. alma ran 90 meters in 17.2 seconds. who had the fastest time
maria [59]

Answer:

Gene ran faster

Step-by-step explanation:

The fastest time is the smallest time since they ran the same distance

gene ran 90 meters in 16.3 seconds.

alma ran 90 meters in 17.2 seconds

16.3 < 17.2

Gene ran faster

7 0
1 year ago
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