Answer:
The width of the rectangular lid is 15 cm.
Step-by-step explanation:1. Let's review the information given to us to answer the question correctly:
Length of the ribbon used by Jun = 56 cmLength of the rectangular lid = 13 cm
2. What is the width of the lid? The ribbon used by Jun is equivalent to the perimeter of the rectangular lid, therefore:Perimeter = 2 * Length + 2 * WidthReplacing with the values we have:56 = 2 * 13 + 2 * Width56 = 26 + 2Width2Width = 56 - 262Width = 30Width = 30/2Width = 15
Answer:

Step-by-step explanation:
Volume of cone = 
Since we are given that a circular cone has a base of radius r and a height of h that is the same length as the radius
=
=
Surface area of cone including 1 base = 
Since r = h
So, area = 
=
= 
Ratio of volume of cone to its surface area including base :



Rationalizing


Hence the ratio the ratio of the volume of the candle to its surface area(including the base) is 
Answer:
ag=74 and ed=83
Step-by-step explanation:
super simple actually
Here, we are required to determine after how many minutes will the two substances be at the same temperature.
The equation of when the two substances will be at the same temperature and the solution are as follows;
(a) The equation is 96.2 + 1.5(x) = 98.5 + 0.8(x).
(b) The solution is, x = 3.285minutes.
For substance A which is currently at 96.2° and rising at 1.5° each minute; It's temperature after x minutes is given as;
For substance B which is currently at 98.5° and rising at 0.8° each minute; It's temperature after x minutes is given as;
(a) For the two substances to be at the same temperature; T(a) must be equal to T(b).
The equation is therefore;.
96.2 + 1.5(x) = 98.5 + 0.8(x)
(b) To determine the solution;
1.5x - 0.8x = 98.5 - 96.2
0.7x = 2.3
x = 2.3/0.7
x = 3.285minutes.
Read more:
brainly.com/question/20248109
Answer:
Gene ran faster
Step-by-step explanation:
The fastest time is the smallest time since they ran the same distance
gene ran 90 meters in 16.3 seconds.
alma ran 90 meters in 17.2 seconds
16.3 < 17.2
Gene ran faster