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Ostrovityanka [42]

3 years ago

9

Hayleigh took a long multiple-choice, end-of-year math test. The ratio of the number of problems Hayleigh got incorrect to the n

umber of problems she got correct is 2:9. If Hayleigh missed 8 questions, how many did she get correct?

1 answer:

timurjin [86]3 years ago

8 0

Answer:

36

Step-by-step explanation:

If sh missed 8, then 8/2 is 4, 4x9 is 36

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Answer:

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Step-by-step explanation:

$\sec \theta =\dfrac{1}{\cos \theta} = \dfrac{Hypotenuse}{Adjacent}$

From the attached triangle drawn below:

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Since we are told that:

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