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Pie
4 years ago
8

Please help

Mathematics
1 answer:
netineya [11]4 years ago
3 0
There were 4 cats and 4 dogs on Monday. 
4 * 5.50 = 22
4 * 8 = 32
22 + 32 = 54
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The equation below is a horizontal line. x = 5 <br> true? or false?
ioda

Is X=5 true or false? the answer is that it is true

7 0
4 years ago
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• Evaluate the expression 16n+4 when n=5<br><br>​
bezimeni [28]

Answer:

84

Step-by-step explanation:

substitute n = 5 into the expression

16n + 4

= 16(5) + 4

= 80 + 4

= 84

4 0
1 year ago
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URGENT. <br>Q) 18, 19, 20
notsponge [240]
18. s = 5r^2 + 7......making r the subject
      s - 7 = 5r^2
      (s - 7) / 5 = r^2...by taking the sqrt of both sides, it eliminates the ^2
     ( sqrt (s-7)/5) = r

19. h = ut - 1/2gt^2....u = 100, t = 1 4/5(or 9/5)...g = 6.4
      h = (100)(9/5) - 1/2(6.4)(9/5^2)
      h = 180 - 1/2(6.4)(3.24)
      h = 180 - 3.2(3.24)
      h = 180 - 10.368
      h = 169.632 or 169 79/125

20. sorry..do not know this one
4 0
3 years ago
Read 2 more answers
A coin weights about 14^-2 pounds. Find the weight of 1000 of coins. Round your answer to the nearest tenth.
yuradex [85]

Answer:

5.1

Step-by-step explanation:

14^-2*1000

7 0
3 years ago
Calculate an estimate of a square root of 119 + 120i
uysha [10]

Answer:

Step-by-step explanation:

Given

z=119+120 i

Let \sqrt{119+120 i}=p+iq

Squaring both sides

119+120 i=p^2-q^2+2ipq

Comparing real and imaginary part

Re(LHS)=Re(RHS)

119=p^2-q^2-----------1

comparing Im(LHS)=Im(RHS)

120=2pq

q=\frac{60}{p}

Substitute q in 1

119=p^2-(\frac{60}{p})^2

p^4-119p^2-(68)^2=0

Let x=p^2

x^2-119x-4624=0

x=frac{119\pm \sqrt{119^2+4\times 4624}}{2}

x=\frac{119\pm 180.71}{2}

we take only Positive value because p^2=x

x=149.85

p^2=149.85

thus p=\pm 12.24

q=\mp 4.90

thus \sqrt{119+120 i}=\pm (12.24+i 4.90)

6 0
4 years ago
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