Find the 12th term of the arithmetic sequence whose common difference is d=6 and whose first term is a, = 2.
1 answer:
Answer:
<h3>The 12th term is 68</h3>
Step-by-step explanation:
Since the sequence is an arithmetic sequence
For an nth term in an arithmetic sequence
A(n) = a + ( n - 1)d
where a is the first term
n is the number of terms
d is the common difference
From the question
d = 6
a = 2
n = 12
So the 12th term of the sequence is
A(12) = 2 + (12-1)6
= 2 + 11(6)
= 2 + 66
<h3>A(12) = 68</h3>
Hope this helps you
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