Question

Find the 12th term of the arithmetic sequence whose common difference is d=6 and whose first term is a, = 2.

Answer 1

Answer:

The 12th term is 68

Step-by-step explanation:

Since the sequence is an arithmetic sequence

For an nth term in an arithmetic sequence

A(n) = a + ( n - 1)d

where a is the first term

n is the number of terms

d is the common difference

From the question

d = 6

a = 2

n = 12

So the 12th term of the sequence is

A(12) = 2 + (12-1)6

= 2 + 11(6)

= 2 + 66

A(12) = 68

Hope this helps you