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Sati [7]
1 year ago
8

Suppose that the relation Tis defined as follows.T= {(3, a), (5, c), (5, d))Give the domain and range of T.Write your answers us

ing set notation.domain=range =I need help with this math problem.
Mathematics
1 answer:
diamong [38]1 year ago
8 0

Given:

The relation T is defined as follows:

T=\lbrace(3,a),(5,c),(5,d)\rbrace

Required:

To give the domain(D) and range(R) of T.

Explanation:

We have the relation T defined as:

T=\lbrace(3,a),(5,c),(5,d)\rbrace

Then the domain(D) of the relation T is,

D=\lbrace3,5,5\rbrace

The range (R) of the relation T is,

R=\lbrace a,c,d\rbrace

Final Answer:

The domain(D) and range (R) of the relation T is,

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iren2701 [21]

Answer:

The lateral area is 624 unit²

Step-by-step explanation:

* Lets explain how to solve the problem

- The regular square pyramid has a square base and four congruent

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- The slant height of it = \sqrt{(\frac{1}{2}b)^{2}+h^{2}}, where

  b is the length of its base and h is the perpendicular height

- Its lateral area = \frac{1}{2}.p.l, p is the perimeter of the base

 and l is the slant height

* Lets solve the problem

∵ The base of the pyramid is a square with side length 24 units

∵ Its perpendicular height is 5 units

∵ The slant height (l) = \sqrt{(\frac{1}{2}b)^{2}+h^{2}}

∴ l = The slant height of it = \sqrt{(\frac{1}{2}.24)^{2}+5^{2}}

∴ l = \sqrt{(12)^{2}+25}=\sqrt{144+25}=\sqrt{169}=13

∴ l = 13 units

∵ Perimeter of the square = b × 4

∴ The perimeter of the base (p) = 24 × 4 = 96 units

∵ The lateral area = \frac{1}{2}.p.l

∴ The lateral area = \frac{1}{2}.(96).(13)

∴ The lateral area = 624 unit²

* The lateral area is 624 unit²

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3 years ago
What is the first numbers of pi?
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kotykmax [81]

Answer:

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Step-by-step explanation:

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