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3 years ago

Find the first three terms of the sequence with nth term 3n-2

Mathematics

1 answer:

kykrilka [37]3 years ago

7 0

Answer:

To find out the first three terms of 3n - 2 substitute 1 ,2 and 3 into the equation.

so the three terms a

3(1)-2=1

3(2)-2=6-2=4

3(3)-2=9-2=7

As you can see the sequence goes up in 1,4 and 7.To find out the 10th term you also substitute 10 into the equation so 3(9)-2=18-2=16

so 16 is the tenth term

Hope this helped!

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A photographer uses an online service to sell some of his work. The amount of money he will make from selling 10 copies of the s

VLD [36.1K]

Answer:

Step-by-step explanation:

The expression representing the amount of money that the photographer would make from selling 10 copies is given as

10(0.75p - 0.5)

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10(0.75 × 5 - 0.5) = $32.5

It could have been

10(5 - 0.5) = $45

The price is being reduced by 25%(100 - 75)

Therefore, the option that most likely describes the agreement between the online service company and the photographer is

A. The company keeps 25% of the amount paid for each copy and charges the photographer $0.50 for every copy purchased.

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3 years ago

Find the value of x and the value of y

WARRIOR [948]

I’m pretty sure it’s b.

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3 years ago

Can someone please help me on number 2 please

andriy [413]

I believe the answer is 0, but I could be wrong!

5 0

3 years ago

You bought a magazine for $5 and some notepads for $3 each. You spent a total of $26. How many notepads did you buy?

german

Answer:

7 notepads

Step-by-step explanation:

5 + 3x = 26

Subtract constant (5)

3x = 21

Divide by coefficient (3)

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8 0

3 years ago

Read 2 more answers

Given that the quadratic equation has equal roots (k^2-1)x^2-2kx-3k-1=0

Alik [6]

Answer:

(See explanation for further details)

Step-by-step explanation:

The real expression is:

$(k^{2}-1)\cdot x{{2} - 2\cdot k \cdot x - 3\cdot k + 1 = 0$

The general equation for the second-order polynomial is:

$x = \frac{2\cdot k \pm \sqrt{4\cdot k^{2}-4\cdot (k^{2}-1)\cdot (-3\cdot k + 1)}}{k^{2}-1}$

This condition must be observed for the case of a quadratic equation with equal roots:

$4\cdot k^{2} - 4\cdot (k^{2}-1)\cdot (-3\cdot k + 1) = 0$

$k^{2} + (k^{2}-1)\cdot (3\cdot k + 1) = 0$

$k^{2} + 3\cdot k^{3} - 3\cdot k - k^{2}-1 = 0$

$3\cdot k^{3} - 3\cdot k - 1 = 0$

7 0

4 years ago

Find the first three terms of the sequence with nth term 3n-2​

Find the first three terms of the sequence with nth term 3n-2