F(x)=x^5 + 5*x^4 - 5*x^3 - 25*x^2 + 4*x + 20
By examining the coefficients of the polynomial, we find that
1+5-5-25+4+20=0 => (x-1) is a factor
Now, reverse the sign of coefficients of odd powers,
-1+5+5-25-4+20=0 => (x+1) is a factor
By the rational roots theorem, we can continue to try x=2, or factor x-2=0
2^5+5(2^4)-5(2^3)-25(2^2)+4(2)+20=0
and similarly f(-2)=0
So we have found four of the 5 real roots.
The remainder can be found by synthetic division as x=-5
Answer: The real roots of the given polynomial are: {-5,-2,-1.1.2}
Answer:
see attached
Step-by-step explanation:
When the sequence of sides (shortest to longest, for example) remains the same (CW or CCW), then the number of reflections is even, possibly zero. The figure will have been <em>translated</em> if all of the corresponding sides retain their original direction, otherwise <em>rotation</em> is involved.
If the sequence is reversed, as in the upper right and lower left figures, then <em>reflection</em> is involved. The line of reflection will be the line through the midpoints of the segments connecting corresponding vertices.
Answer:
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Step-by-step explanation:
I think The answer is 2920