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4 years ago

Which expression represents the total surface area, in square centimeters, of the square pyramid?

Mathematics

1 answer:

Dafna1 [17]4 years ago

7 0

Answer:

(8.2) (8.2) + 4 (one-half (8.2) (11.1))

Step-by-step explanation:

Formula for calculating the surface area of a square based pyramid is expressed as:

Surface area = A + 1/2ps

A is the base area

P is the perimeter of base

S is the slant side.

Since the base of the pyramid is a square, then

Base Area A = L²

A = 8.2²

A = 67.24cm²

Perimeter of square = 4L = 4(8.2)

= 32.8cm

Slant Height = 11.1cm

On substituting the gotten value:

Surface area = 8.2(8.2) + 1/2 [4(8.2 (11.1)]

Based on the solution above, the expression below is correct.

S =(8.2) (8.2) + 4 (one-half (8.2) (11.1))

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During seventh grade Athletics 34 of the 87 girls are in off season lifting weights what are the what percentage of the girls ar

laiz [17]

Answer: 61% or exactly 60.9%

Step-by-step explanation:

if 34 are lifting weights then 53 (87-34) are not lifting weights and the percentage of 53/87 is 61%

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3 years ago

Read 2 more answers

If the average yield of cucumber acre is 800 kg, with a variance 1600 kg, and that the amount of the cucumber follows the normal

lorasvet [3.4K]

Answer:

The percentage is

$P(x_1 < X < x_2 ) = 51.1 \%$

The probability is $P(Z > 2.5 ) = 0.0062097$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 800$

The variance is $var(x) = 1600 \ kg$

The range consider is $x_1 = 778 \ kg \ x_2 = 834 \ kg$

The value consider in second question is $x = 900 \ kg$

Generally the standard deviation is mathematically represented as

$\sigma = \sqrt{var (x)}$

substituting value

$\sigma = \sqrt{1600}$

$\sigma = 40$

The percentage of a cucumber give the crop amount between 778 and 834 kg is mathematically represented as

$P(x_1 < X < x_2 ) = P( \frac{x_1 - \mu }{\sigma} < \frac{X - \mu }{ \sigma } < \frac{x_2 - \mu }{\sigma } )$

Generally $\frac{X - \mu }{ \sigma } = Z (standardized \ value \ of \ X)$

$P(x_1 < X < x_2 ) = P( \frac{778 - 800 }{40} < Z< \frac{834 - 800 }{40 } )$

$P(x_1 < X < x_2 ) = P(z_2 < 0.85) - P(z_1 < -0.55)$

From the z-table the value for $P(z_1 < 0.85) = 0.80234$

and $P(z_1 < -0.55) = 0.29116$

$P(x_1 < X < x_2 ) = 0.80234 - 0.29116$

$P(x_1 < X < x_2 ) = 0.51118$

The percentage is

$P(x_1 < X < x_2 ) = 51.1 \%$

The probability of cucumber give the crop exceed 900 kg is mathematically represented as

$P(X > x ) = P(\frac{X - \mu }{\sigma } > \frac{x - \mu }{\sigma } )$

substituting values

$P(X > x ) = P( \frac{X - \mu }{\sigma } >\frac{900 - 800 }{40 } )$

$P(X > x ) = P(Z >2.5 )$

From the z-table the value for $P(Z > 2.5 ) = 0.0062097$

7 0

4 years ago

-5x+1+2x+2=-2+2x<br> I’m super lost

DaniilM [7]

Are you trying to simplify the equation? if so, combine the like terms on each side first. -3x + 3 = -2 + 2x. Then simplify, -5x = -5. And solve, x = 1

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3 years ago

What is the equation of the line

Bas_tet [7]

Answer:

3.4

Step-by-step explanation:

the answer would be 3.4

6 0

3 years ago

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If a large marshmallow has a volume of 3.00in3 and density of 0.242 g/cm3, how much would it weigh in grams? 1 in3=16.39 c

KengaRu [80]

A volume:
V = 3.00 in³
1 in³ = 16.39 cm³
V = 3.00 · 16.39 = 49.17 cm³
0.242 g/cm³ · 49.17 g = 11.899 g² ≈ 11.90 g
Answer: It would weigh 11.90 grams.

8 0

3 years ago