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3 years ago

Rachel ate 1 4/6 brownies, and brandy ate 6/7 of a brownie. how many brownies did they eat altogether?

Mathematics

2 answers:

In-s [12.5K]3 years ago

6 0

Answer:

53/21 OR 2 11/21

Step-by-step explanation:

1 4/6 + 6/7

Change 1 4/6 into an improper fraction

1 4/6 6x1= 6+4= 10/6

Simplify 10/6 --> 5/3

5/3+ 6/7

find a common denominator (21)

35/21+18/21= 53/21

mixed number form is 2 11/21

Vikki [24]3 years ago

5 0

Answer:

$2 \frac{11}{21}$

Step-by-step explanation:

1 4/6 + 6/7 = 2 11/21

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After taking a 70 point test, a student guesses that he got 65 points correct. Later he finds out he got 67 points

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Answer:

Percent error = 4.29%

Step-by-step explanation:

Percent error can be defined as a measure of the extent to which an experimental value differs from the theoretical value.

Mathematically, it is given by this expression;

$Percent \; error = \frac {experimental \;value - theoretical \; value}{ theoretical \;value} *100$

Given the following data;

Experimental value = 67

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Substituting into the equation, we have;

$Percent \; error = \frac {67 - 70 }{ 70} *100$

$Percent \; error = \frac {3}{70} *100$

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3 years ago

Read 2 more answers

Describe the steps to dividing imaginary numbers and complex numbers with two terms in the denominator?

zlopas [31]

Answer:

Let be a rational complex number of the form $z = \frac{a + i\,b}{c + i\,d}$ , we proceed to show the procedure of resolution by algebraic means:

1) $\frac{a + i\,b}{c + i\,d}$ Given.

2) $\frac{a + i\,b}{c + i\,d} \cdot 1$ Modulative property.

3) $\left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)$ Existence of additive inverse/Definition of division.

4) $\frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}$ $\frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}$

5) $\frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}$ Distributive and commutative properties.

6) $\frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)}$ Distributive property.

7) $\frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}}$ Definition of power/Associative and commutative properties/ $x\cdot (-y) = -x\cdot y$ /Definition of subtraction.

8) $\frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}}$ Definition of imaginary number/ $x\cdot (-y) = -x\cdot y$ /Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.

Step-by-step explanation:

Let be a rational complex number of the form $z = \frac{a + i\,b}{c + i\,d}$ , we proceed to show the procedure of resolution by algebraic means:

1) $\frac{a + i\,b}{c + i\,d}$ Given.

2) $\frac{a + i\,b}{c + i\,d} \cdot 1$ Modulative property.

3) $\left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)$ Existence of additive inverse/Definition of division.

4) $\frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}$ $\frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}$

5) $\frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}$ Distributive and commutative properties.

6) $\frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)}$ Distributive property.

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2 years ago

Calculate simple interest :

Elodia [21]

Answer:

the simple interest in both cases is 200 and 756 respectively

Step-by-step explanation:

The computation of the simple interest is shown below:

As we know that

Simple interest = P × r% × t

a. Simple interest is

= 2,500 × 8% × 1

= 200

b. The simple interest is

= 4,200 × 6% × 3

= 756

Hence, the simple interest in both cases is 200 and 756 respectively

5 0

3 years ago

Rachel ate 1 4/6 brownies, and brandy ate 6/7 of a brownie. how many brownies did they eat altogether?​

Rachel ate 1 4/6 brownies, and brandy ate 6/7 of a brownie. how many brownies did they eat altogether?