Answer:
appx. 1.07 moles
Explanation:
175g of molecule Ca(NO3)2
To find the # of moles, use stoichoimetry.
1. We need the molar mass of Ca(NO3)2.
Ca mass: 40.08 g
NO3 mass: N + 3(O) --> 14.01 + 3(16.00) --> 62.01
Molar mass = Ca + 2(NO3) --> 40.08 + 2(62.01) --> 164.1 g
2. write out the calculation
175g Ca(NO3)2 * (1 mole Ca(NO3)2)/(molar mass of Ca(NO3)2)
175 g Ca(NO3)2 * (1 mole Ca(NO3)2)/(164.1 g Ca(NO3)2)
The g units cancel out and we're left with moles.
Simply perform the calculation now: 175*1/164.1 ≅1.07 moles
It is D. because the student is using a <span> thermometer and a rain gauge </span>
Answer:
3.74L
Explanation:
PV=nRT
V=nRT/P
= 0.25mol*0.0821LatmK^-1*273k/1.50atm
=3.74L